**Title: E1 Elimination Reaction: Predicting Reagents****Objective:**To determine the reagents necessary to complete an E1 elimination reaction.**Initial Compound:**A bromine-substituted benzene ring is presented as the starting material.**Reaction Details:**The reaction involves an E1 elimination process where the goal is to transform the starting material into a compound with a new double bond.**Reagent Options:**- **A:** H₃O⁺ and heat- **B:** NaH and heat- **C:** (CH₃)₃COK and heat- **D:** CH₃OH- **E:** CH₃OH and heat**Correct Reagent:** Option **C** ((CH₃)₃COK and heat) is selected as the appropriate reagent for this E1 elimination reaction. **Resulting Compound:**The product of the reaction is a benzene ring with an additional double bond between the carbon atoms previously bonded to bromine and the adjacent carbon.**Conclusion:**For the successful completion of this E1 elimination reaction, the use of potassium tert-butoxide ((CH₃)₃COK) in the presence of heat is essential to achieve the desired product formation. In an E2 elimination reaction, the leaving group and the hydrogen atom must be anti-coplanar for this concerted reaction to occur.Identify which of the following structures has the hydrogen atom and the leaving group aligned anti-coplanar.**Structures:**1. **Structure I:** - Br - H - H - Ph - F - CH₃2. **Structure II:** - CH₃ - H - Ph - Ph - Br3. **Structure III:** - H - H - Ph - Ph - CH₃ - OH**Options for Answer:**- A) I- B) II- C) III**Explanation:**Identify the structure in which the hydrogen atom and the leaving group (e.g., Br, OH) are positioned opposite each other, allowing for the required anti-coplanar arrangement for an E2 reaction.

When alkyl halides are treated with weak base, it undergoes E1 elimination to give alkene.The E1 elimination is a two step, step-,1 loss of leaving group forming carbocation and step-2, is removal of beta hydrogen to form pi-bond.When alkyl halides are treated with strong base, it undergoes E2 elimination to give alkene.The E2 elimination is a single step, concerted with leaving group (halide ion) and hydrogen anti co-planar arrangement.E1 reaction requires weak base and heat, among the given reagent weak base is methanol alone.So, the reagent for E1 reaction is methanol and heat, option E.Other options are strong bases or heating is not there, so others are wrong option.E2 requires the hydrogen and the leaving group in the anti coplanar orientation.Structure 2: Has the leaving group, bromine and the hydrogen in the anticoplanar arrangement.The hydrogen and the leaving group which are anti coplanar are in red colour.Structure 3: Has alcohol group(leaving group) with hydrogen in its anti position.Wrong options:The structure 1: Has methyl group anti to the leaving group bromine, so wrong.The reagent used for the given E1 reaction is methanol and heat.The structures that have hydrogen and leaving group in anti-coplanar arrangement areStructure II and III.