Rank the following in order of reactivity in an E1 reaction, (1 = most reactive in an E1 reaction; 3 = least reactive in an E1 reaction). The image contains three structural representations of brominated hydrocarbons.1. **Left Structure**: - This molecule has a bromo (Br) group attached to a branched alkane. The bromo group is on the second carbon of a three-carbon side chain with a central branching forming an isopropyl group.2. **Middle Structure**: - This structure depicts a longer carbon chain with a bromine atom. The Br is attached to the first carbon in a linear hexane chain, forming a primary bromoalkane.3. **Right Structure**: - Similar to the left structure, this molecule also has a bromine atom attached to a branched carbon chain. The Br is at the second carbon of a butane chain, creating a secondary bromide in a branched configuration.These diagrams illustrate various positions where the bromine atom can be attached within different hydrocarbon structures, showcasing examples of isomers in organic chemistry.

Elimination reaction of alkyl halide: Alkyl halide gives an elimination reaction by reacting with a strong base. E1 reaction involves a two-step mechanism in which carbon-halogen bonds break in the first step to form a carbocation intermediate and in the second step, the carbocation intermediate donates a hydrogen ion to form an alkene.The carbocation formation reaction is the slow step and the rate of reaction depends on the slow step. Hence, we can say that the rate of E1 reaction of the different alkyl bromides can be compared by comparing the stability of the carbocation intermediate.The stability of the carbocation formed by the given alkyl halide is as follows:The most stable carbocation will be formed easily and it will give the fastest E1 reaction. Hence the order of the reactivity of the E1 reaction is as follows: