PRACTICE PROBLEM 11.13 V 20 92 ww 30 92 -j10 92 j20 92 60 92 Figure 11.25 For Practice Prob. 11.13. In the circuit in Fig. 11.25, the 60-2 resistor absorbs an average power of 240 W. Find V and the complex power of each branch of the circuit. What is the overall complex power of the circuit? Answer: 240.67/21.45° V (rms); the 20-2 resistor: 656 VA; the (30-j10) 22 impedance: 480-j160 VA; the (60+ j20) S2 impedance: 240 +j80 VA; overall: 1376 - j80 VA.

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PRACTICE PROBLEM 11.13
V
20 92
ww
30 92
--j10 9
j20 92
60 92
Figure 11.25 For Practice Prob. 11.13.
In the circuit in Fig. 11.25, the 60-2 resistor absorbs an average power
of 240 W. Find V and the complex power of each branch of the circuit.
What is the overall complex power of the circuit?
Answer: 240.67/21.45° V (rms); the 20-2 resistor: 656 VA; the
(30-j10) 22 impedance: 480-j160 VA; the (60+ j20) S2 impedance:
240 +j80 VA; overall: 1376 - j80 VA.
Transcribed Image Text:PRACTICE PROBLEM 11.13 V 20 92 ww 30 92 --j10 9 j20 92 60 92 Figure 11.25 For Practice Prob. 11.13. In the circuit in Fig. 11.25, the 60-2 resistor absorbs an average power of 240 W. Find V and the complex power of each branch of the circuit. What is the overall complex power of the circuit? Answer: 240.67/21.45° V (rms); the 20-2 resistor: 656 VA; the (30-j10) 22 impedance: 480-j160 VA; the (60+ j20) S2 impedance: 240 +j80 VA; overall: 1376 - j80 VA.
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