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Positive charge Q is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure Q 0 dQ ds X dE P dE ya 1 of 3 > dE x Your results for smaller values of x are plotted in (Figure 3) as E/x versus x. Why does E/x approach a constan value as a approaches zero. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Ez = Ez Ez Ex Ez = Ez kQ x a = kQ (x²+a²) E = kQx a² = kQx (x²+a²) kQx Ez = a³ Ez kQ I a² E₂ x kQx a kQx (x²+a²)³/2 kQ a³ P Pearson = Reset Help The electric field along the axis a distance from the ring is For

Positive charge Q is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure Q 0 dQ ds X dE P dE ya 1 of 3 > dE x Your results for smaller values of x are plotted in (Figure 3) as E/x versus x. Why does E/x approach a constan value as a approaches zero. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Ez = Ez Ez Ex Ez = Ez kQ x a = kQ (x²+a²) E = kQx a² = kQx (x²+a²) kQx Ez = a³ Ez kQ I a² E₂ x kQx a kQx (x²+a²)³/2 kQ a³ P Pearson = Reset Help The electric field along the axis a distance from the ring is For

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Positive charge is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure dQ ds r=Vr X dE dEx a 1 of 3 > dE X Review | Constants Your results for smaller values of x are plotted in (Figure 3) as E/x versus x. Why does E/x approach a constan value as x approaches zero. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Ex Ex Ex Ex = Ex X Ex Ex Ex X Ex X kQx a² kQ (x²+a²) = kQ a kQx (x²+²) kQx a kQx a³ kQ a² kQx 3/2 (x²+a²)³/² kQ 3 P Pearson Reset The electric field along the axis a distance from the ring is Help For <a, this gives and so E/x approach a constant value of as x approaches zero.
Transcribed Image Text:Positive charge is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure dQ ds r=Vr X dE dEx a 1 of 3 > dE X Review | Constants Your results for smaller values of x are plotted in (Figure 3) as E/x versus x. Why does E/x approach a constan value as x approaches zero. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Ex Ex Ex Ex = Ex X Ex Ex Ex X Ex X kQx a² kQ (x²+a²) = kQ a kQx (x²+²) kQx a kQx a³ kQ a² kQx 3/2 (x²+a²)³/² kQ 3 P Pearson Reset The electric field along the axis a distance from the ring is Help For <a, this gives and so E/x approach a constant value of as x approaches zero.
Positive charge is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure a dQ ds r=V X dE dEx Va 1 of 3 dE X Part A Your results for the larger values of x are plotted in (Figure 2) as Ex² versus x. Why does the quantity Ex² approach a constant value as x increases. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. proportional to x Submit point charge Part C constant charged plane -2 Request Answer Part B Complete previous part(s) P Pearson Review | Constants Reset Help Far from the ring, at large values of x, the ring can be considered as a constant value as x increases. So its electric field at large values of x is hence Ex² approaches a
Transcribed Image Text:Positive charge is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure a dQ ds r=V X dE dEx Va 1 of 3 dE X Part A Your results for the larger values of x are plotted in (Figure 2) as Ex² versus x. Why does the quantity Ex² approach a constant value as x increases. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. proportional to x Submit point charge Part C constant charged plane -2 Request Answer Part B Complete previous part(s) P Pearson Review | Constants Reset Help Far from the ring, at large values of x, the ring can be considered as a constant value as x increases. So its electric field at large values of x is hence Ex² approaches a
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