4. Cathode ray tubes (CRTS) used in old- style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.50 cm. If the potential difference across the plates was 25.0 kV, find the magnitude of the electric field in the region between the plates.

4. Cathode ray tubes (CRTS) used in old- style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.50 cm. If the potential difference across the plates was 25.0 kV, find the magnitude of the electric field in the region between the plates.

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter18: Electric Charge And Electric Field

Section: Chapter Questions

Problem 53PE: A simple and common technique for accelerating electrons is shown in Figure 18.55, where there is a...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

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Can you help solve for the answers to question 4 and 5?

4. Cathode ray tubes (CRTs) used in old-
style televisions have been replaced by
modern LCD and LED screens. Part of
the CRT included a set of accelerating
plates separated by a distance of about
1.50 cm. If the potential difference across
the plates was 25.0 kV, find the
magnitude of the electric field in the
region between the plates.
5. A constant electric field accelerates a
proton from rest through a distance of
2.00 m to a speed of 1.50 × 105 m/s.
a. Find the change in the proton's
kinetic energy.
Answer
b. Find the change in the system's
electric potential energy.
Answer
c. Calculate the magnitude of the
electric field.

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A simple and common technique for accelerating electrons is shown in Figure 18.55, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electorn if the field strength is 2.50104 N/C. (b) Explain why the electron will not be pulled back to the positive plate once it moves through the hole.
An electron is to be accelerated in a uniform electric field having a strength of 2.00106 V/m. (a) What energy in keV is given to the electron if it is accelerated through 0.400 m? (b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV?
In nuclear fission. a nucleus splits roughly in half. (a) What is the potential 2.00 10-14 m from a fragment that has 46 protons in it? (b) What is the potential energy in MeV of a similarly charged fragment at this distance?
A simple and common technique for accelerating electrons is shown in Figure 7.46, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving, (a) Calculate the acceleration of the electron if the field strength is 2.50104 N/C . (b) Explain why the electron will not be pulled back to the positive plate once it moves through the hole. Figure 7.46 Parallel conducting plates with opposite charges on them create a relatively uniform electric field used to accelerate electrons to the right. Those that go through the hole can be used to make a TV or computer screen glow or to produce X- rays.
The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50104 V/m. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 3.00 cm from the other?
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Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field strength between them, if the potential 8.00 cm from the zero volt plate (and 2.00 cm from the other) is 450 V? (b) What is the voltage between the plates?
A proton accelerates from rest in a uniform electric field of 640. N/C At some later time, its speed is 1.20 106 m/s. (a) Find the magnitude of the acceleration of the proton. (b) How long does it take the proton to reach this speed? (c) How far has it moved in that interval? (d) What is its kinetic energy at the later time?