Please solve asap and explain how you reached that solution properly. Thank you in advance! You have two capacitors with capacities of 50 pF and 100pF respectively. If you want to have less capacity, you can:connect the capacitors indifferently in series or in parallelconnect the capacitors in parallel, thus obtaining a capacitance equal to 45.45pFswap the capacitor of higher capacity with the one of lower capacityconnect the capacitors in series, thus obtaining a capacitance equal to 33.33pF

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Answered: You have two capacitors with capacities…

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