Position vector of a particle is given as r(t) = 2t² i + 5tj - 3k in meters where t is in seconds. What is the power of the force F (t) = 100i + 20j + 120k Newton at t = 2 s?
Position vector of a particle is given as r(t) = 2t² i + 5tj - 3k in meters where t is in seconds. What is the power of the force F (t) = 100i + 20j + 120k Newton at t = 2 s?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Question:
The position vector of a particle is given as \(\mathbf{r}(t) = 2t^2 \mathbf{i} + 5t \mathbf{j} - 3 \mathbf{k}\) in meters where \(t\) is in seconds.
What is the power of the force \(\mathbf{F}(t) = 100 \mathbf{i} + 20 \mathbf{j} + 120 \mathbf{k}\) in Newton at \(t = 2 \, s\)?
### Options:
- \( \bigcirc \) 1000 W
- \( \bigcirc \) 540 W
- \( \bigcirc \) 1260 W
- \( \bigcirc \) 900 W](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c67b105-1a8e-425b-a8ad-195f3df08909%2F78071868-9405-4471-b129-39722d61ebd9%2Fj5780sb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question:
The position vector of a particle is given as \(\mathbf{r}(t) = 2t^2 \mathbf{i} + 5t \mathbf{j} - 3 \mathbf{k}\) in meters where \(t\) is in seconds.
What is the power of the force \(\mathbf{F}(t) = 100 \mathbf{i} + 20 \mathbf{j} + 120 \mathbf{k}\) in Newton at \(t = 2 \, s\)?
### Options:
- \( \bigcirc \) 1000 W
- \( \bigcirc \) 540 W
- \( \bigcirc \) 1260 W
- \( \bigcirc \) 900 W
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