**Problem Statement:** With an initial diameter of 10 mm, an A-36 steel wire is connected at ends B and C. The weight of bar AB is negligible along with any friction in the pins. The area contraction of wire BC cannot exceed 0.0028%. What is the mass of the heaviest possible uniform cylinder supported as shown in the figure? **Diagrams and Explanation:** The diagram on the right illustrates the geometrical setup and the forces involved: - The wire BC is fixed to two points, B and C, which are 6 meters apart horizontally. - A bar AB, 6 meters long, is connected to a point A and pin B. - A uniform cylinder is suspended under the bar AB. - The vertical distance from point A to point C is 4 meters. The geometry forms a right triangle with: - AC (vertical side) = 4 meters - BC (hypotenuse) = 6 meters (horizontally between points B and C) - AB (bar) = 6 meters inclined. **Objective:** To determine the mass of the heaviest possible uniform cylinder supported, considering the limitations given by the area contraction of the wire. This involves analyzing the forces in play, ensuring the wire's elongation does not exceed the allowable area contraction (0.0028%). This problem utilizes principles from statics and material mechanics to find the maximum allowable load on the wire without exceeding its elastic limit.
**Problem Statement:** With an initial diameter of 10 mm, an A-36 steel wire is connected at ends B and C. The weight of bar AB is negligible along with any friction in the pins. The area contraction of wire BC cannot exceed 0.0028%. What is the mass of the heaviest possible uniform cylinder supported as shown in the figure? **Diagrams and Explanation:** The diagram on the right illustrates the geometrical setup and the forces involved: - The wire BC is fixed to two points, B and C, which are 6 meters apart horizontally. - A bar AB, 6 meters long, is connected to a point A and pin B. - A uniform cylinder is suspended under the bar AB. - The vertical distance from point A to point C is 4 meters. The geometry forms a right triangle with: - AC (vertical side) = 4 meters - BC (hypotenuse) = 6 meters (horizontally between points B and C) - AB (bar) = 6 meters inclined. **Objective:** To determine the mass of the heaviest possible uniform cylinder supported, considering the limitations given by the area contraction of the wire. This involves analyzing the forces in play, ensuring the wire's elongation does not exceed the allowable area contraction (0.0028%). This problem utilizes principles from statics and material mechanics to find the maximum allowable load on the wire without exceeding its elastic limit.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:**Problem Statement:**
With an initial diameter of 10 mm, an A-36 steel wire is connected at ends B and C. The weight of bar AB is negligible along with any friction in the pins. The area contraction of wire BC cannot exceed 0.0028%. What is the mass of the heaviest possible uniform cylinder supported as shown in the figure?
**Diagrams and Explanation:**
The diagram on the right illustrates the geometrical setup and the forces involved:
- The wire BC is fixed to two points, B and C, which are 6 meters apart horizontally.
- A bar AB, 6 meters long, is connected to a point A and pin B.
- A uniform cylinder is suspended under the bar AB.
- The vertical distance from point A to point C is 4 meters.
The geometry forms a right triangle with:
- AC (vertical side) = 4 meters
- BC (hypotenuse) = 6 meters (horizontally between points B and C)
- AB (bar) = 6 meters inclined.
**Objective:**
To determine the mass of the heaviest possible uniform cylinder supported, considering the limitations given by the area contraction of the wire. This involves analyzing the forces in play, ensuring the wire's elongation does not exceed the allowable area contraction (0.0028%).
This problem utilizes principles from statics and material mechanics to find the maximum allowable load on the wire without exceeding its elastic limit.
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