Polypeptides are continuously synthesized and broken down within living systems. One ofthese processes is shown in the figure below.H|HH'c| HH-N-!CDاR₂CاR₁o=Uo=UA polypeptide reactionI-Z2-1H- بےے| H ||u=0=0=-I-Ź-N-H |----HOo=---R3--|--OHI-U=02-1--U=OH1-2Aa polypeptide chain that folds to form the tertiary structureBa polypeptide chain that is denatured into the primary structurea chain of amino acids linked by dehydration synthesisH-UCاo=RsWhich of the following provides the best description of the reaction shown in the figure?----2-1a polypeptide chain that is broken down through a hydrolysis reactionHo=I-ZC - OHo=n- بےC - OHv=0

A protein is a chain of amino acids which can be called a polypeptide. The polypeptide chain folds…

Answered: Polypeptides are continuously…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Indicate next to each letter the name of the monomers shown below and write the name of the polymer that is produced from the monomer. H-C-OH HỌ-C-H H-C-OH H-C-OH о- 6 CH₂OH 0=P-O О CH₂ Phosphate H group А: Name of polymer: H- Н Н OH H Sugar Н Н. H Nitrogenous base (adenine) C: 0 НО Name of polymer: H C-C-N CH2 SH Н НИ Н III H-N-С-С-0 +111 НКН н B: Name of polymer: Н 0 0-C-H o Н-С-0² H-C-O H S ННННННННННН Н Н Н LI -CH Н ННННННННННН Н Н Н ITIILE I C-C H ...... С-с-с-с-с-с-с III E .. ННННННННННН Н Н С-С-f 111 1 FE D: I НННННННННННННН No polymer!
Although the first two carbons of fructose and glucose are identical in structure to DHAP and GADP (from glycolysis), DHAP and GADP equilibriate on their in solution to favor the ketone over the aldehyde, while fructose and glucose do not. Why? a)The larger size of the molecule sterically hinders the isomerization b)The larger sugars have more OH groups which hydrogen bond and disrupt isomerization c)The larger sugars cyclize, and there is no carbonyl to isomerize in the cyclic form d)The larger sugars cyclize, and in the cyclic form the hydrogen bonding is very strong e)The larger sugars are less soluble in water than the smaller sugars
Explain these diagrams
This image is showing the conformations of ubiquitin superimposed. What do the structures in this figure tell us about the dynamics of enzymes? Discuss the limitations of crystal structures in the analysis of proteins. What are the benefits? What are the advantages of NMR structures?
What type of molecule is shown here? Give its biological importance?
HO molecule E HO. (CH12 CH, OH NH, HO molecule F HO molecule D molecule C H,C-(CH),3 of H,C-(CH,) H,C-(CH molecule B H3C-(CHa)12 H,C-(CH) но molecule A
Identify what type of chemical interactions is involved in the following side chains of the peptide chain below: 3 H-Q 0-H 5. OH OH CH, 6. 9. 4. -- CH, 2. 200 CH, 12 CH CH, -NH,0-C 4 1. 15 3. CH.-OH O CH. 17 18 The following choices can be applied for the following type of chemical interactions. 20 21 Write: AB - if it is a salt bridge or ionic bond CD - if it's a H-bonding 23 24 EF - if it's a hydrophobic interactions GH - if it's a disulfide bond
Draw a curved arrow mechanism for the reaction, adding steps as necessary. Be sure to include all electrons that are necessary to the mechanism and all nonzero formal charges. о :0- 0-н .0. + Add/Remove step Click and drag to start drawing a structure.
Bromelain is a protease, therefore it breaks down the polymer ________ releasing __________ monomers as seen above. This is a ________ type of reaction. List of answers: sucrose fructose dipeptide amino acid polysaccharide glycolipids glucose polypeptide hydrolysis maltose primary protein galactose disaccharide dehydration synthesis lactose glycoproteins ribose deoxyribose nucleotide
Create an oligopeptide via dehydration synthesis using the following amino acids. O. H Tryptophan (TRP) C-C-N но сн, C-C-N. но Glycine (GLY) H H HN
Submit a drawing of the following phospholipid: -x-group is phosphoserine (use google if you need to) -C1 tail is C18:0 -C2 tail is C20:2n-3 Draw at physiological pH, and with correct bond angles.

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