Polypeptides are continuously synthesized and broken down within living systems. One ofthese processes is shown in the figure below.H|HH'c| HH-N-!CDاR₂CاR₁o=Uo=UA polypeptide reactionI-Z2-1H- بےے| H ||u=0=0=-I-Ź-N-H |----HOo=---R3--|--OHI-U=02-1--U=OH1-2Aa polypeptide chain that folds to form the tertiary structureBa polypeptide chain that is denatured into the primary structurea chain of amino acids linked by dehydration synthesisH-UCاo=RsWhich of the following provides the best description of the reaction shown in the figure?----2-1a polypeptide chain that is broken down through a hydrolysis reactionHo=I-ZC - OHo=n- بےC - OHv=0

A protein is a chain of amino acids which can be called a polypeptide. The polypeptide chain folds…

Answered: Polypeptides are continuously…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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the complete hydrolysis of this compound gives - -- and --- (Write the amino acids name in three-letter abbreviations) НООС CH, CH, CH3 CH, NH,CHCNHĊHCNHĊHCOOH Your answer
Which of the following molecular formulas would be for an aldopentose? C4H8O4 C₂H₁408 C6H12O6 C5H1005 D
Which of these statements about the tertiary structure of a polypeptide is(are) untrue? You may select more than one answer. The tertiary structure will be maintained when the solvent is changed from pure water to aqueous acetic acid. O The tertiary structure is determined in part by the formation of disulfide bridges. Hydrogen bonding interactions are responsible for formation of secondary structure but not tertiary structure, O The tertiary structure is rigid and unchanging. O Charge-charge (electrostatic) interactions can be important in the tertiary structure.
Curved arrows are used to illustrate the flow of electrons. Using the provided starting structure, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Then draw any missing organic intermediates or products for this epoxidation reaction. Include all lone pairs in the structures. Ignore inorganic byproducts, counterions, and solvents. 0. ~ H :OH: H Q H --0 Q mCPBA dilute HCI Select to Draw Intermediate 0:0 NaOH :OH: H Select to Add Arrows H I I I I I I I I I I
Write a sample chemical reaction of chymotrypsin in a complete balanced equation label the following properly: substrate/s, cosubstrate/s, and cofactor/s Show all the changes in the reacting components small molecules should be in their skeletal form large molecules could be shown as hybrid structures - reacting/interacting groups in skeletal form, the rest of the molecule as abbreviations/blocks/shapes
1) Which of the following statement(s) regarding the ends of polysaccharides are true? All polysaccharides have at least one reducing end. Some polysaccharides may have no reducing end. Some polysaccharides may have no non-reducing ends. All polysaccharides have a N-glycosidic bond at their reducing ends. none of the above 2) The transformation of a monosaccharide into its ______ occurs easily and does not require the assistance of a catalyst. epimer anomer sugar alcohol diastereomer zwitterion
Explain these diagrams
Describe the quarternary structure of the enzyme aspartate transcarbamoylase: Dodecamer Monomer Tetramer Hexamer Decamer
Create an oligopeptide via dehydration synthesis using the following amino acids. O. H Tryptophan (TRP) C-C-N но сн, C-C-N. но Glycine (GLY) H H HN
Consider the following cyclic monosaccharide. CH₂OH H H H H OH HO OH Part 1 of 2 OH H Classify the monosaccharide as an aor ẞ isomer. Select the single best answer. ○ẞ isomer a isomer Part: 1/2 Part 2 of 2 Draw the other isomer of the cyclic form using a Haworth projection. Click and drag to start drawing a structure. ם' G
Consider the structure shown below. он 3 5 CH; O CH, O H CH; O 1 H-N-CH,-C-N-CH;-C-N-CH-C-N-CH-C-N-CH-C-ơ 2 H. H H Fill in the blank with an integer (1, 2, 3, 4, 5..) as shown in the diagram or to represent a specified number. A hydrophilic side chain is indicated by the number
The figure below illustrates the molecular structures of two fatty acids. A B H₂C The structural formula of erucic acid and behenic acid с H₂C D erucic acid behenic acid Which of the following best explains why erucic acid is liquid at room temperature but behenic acid is solid at room temperature? O OH The presence of a double carbon to carbon bond in erucic acid prevents the molecule from packing closely together. The lack of any double carbon-carbon bonds in behenic acid causes the molecule to be come polar and therefore packed more tightly. The larger number of carbon atoms in erucic acid prevents the molecule from packing tightly together. OH The smaller number of carbon atoms in behenic acid creates stronger covalent bonds between the carbon atoms allowing for them to pack more tightly together.

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