Pls answer the very last question. “ suppose that lll-2 and lll-5 were to have a child. What is the probability that their first child will be have the disorder?” Refer to the pedigree below for this question. Individuals who are shaded have a rare autosomal recessive disorder. Those who are not shaded have the dominant phenotype. Let"A' and "a" represent the dominant and recessive alleles, respectively. Fill in the probability functions below to indicate the genotype or probability function for the genotype ofeach individual. Give all probabilities as fractions that are simplified to the lowest value. Type your fractions in #/# format without spaces. For example, one-half shouldbe typed as 1/2. Place a zero in each space that does not have a number. Failure to follow these instructions will result in your answer being marked as incorrect. Notethat two of the individuals have been completed for you as examples.Individual 1-3 is genotype 0 AA + 1 Aa + 0 aaIndividual Il-4 is genotype 1/3 AA + 2/3 Aa + 0O aIndividual l-6 is genotypeAA +Aa +aaIndividual Il-1 is genotypeAA +Aa +aaIndividual II-5 is genotypeAA +Aa +aaIndividual Il-7 is genotypeAA +Aa +aaIndividual IlI-2 is genotypeAA +Aa +aaIndividual IlII-5 is genotypeAA +Aa +aaFor the next question, give the probability as a fraction that is simplified to the lowest value. Type your fraction in the format #/# with no spaces.Suppose that Ill-2 and Ill-5 were to have a child. What is the probability that their first child will be have the disorder?

To have an autosomal recessive disorder, one must inherit two mutated genes, one from each parent.…

Answered: Pls answer the very last question. “…

Pls answer the very last question. “ suppose that lll-2 and lll-5 were to have a child. What is the probability that their first child will be have the disorder

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 14QP: A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known...

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Refer to the pedigree below for this question. Individuals who are shaded have a rare autosomal recessive disorder. Those who are not shaded have the dominant phenotype. Let "A' and "a" represent the dominant and recessive alleles, respectively. Fill in the probability functions below to indicate the genotype or probability function for the genotype of each individual. Give all probabilities as fractions that are simplified to the lowest value. Type your fractions in ## format without spaces. For example, one-half should be typed as 1/2. Place a zero in each space that does not have a number. Failure to follow these instructions will result in your answer being marked as incorrect. Note that two of the individuals have been completed for you as examples. Individual 1-3 is genotype O AA + 1 Aa +0 aa Individual II-4 is genotype 1/3 AA + 2/3 Aa + 0 aa Individual 1-6 is genotype AA + Aa + aa Individual II-1 is genotype Aa + AA + aa Individual II-5 is genotype AA + Aa + aa Individual II-7…
Refer to the pedigree below for this question. Individuals who are shaded have a rare autosomal recessive disorder. Those who are not shaded have the dominant phenotype. Let "A' and a represent the dominant and recessive alleles, respectively. Fill in the probability functions below to indicate the genotype or probability function for the genotype af each individual. Give all probabilities as fractions that are simplified to the lowest value. Type your fractions in ## format without spaces. For example, one-half should be typed as 1/2. Place a zero in each space that does not have a number. Individual 3 is genotype 0 AA + 1 Aa + 0 aa Individual Il-4 is genotype 1/3 AA + 2/3 Aa + 0 aa Individual -1 is genotype AA + Aa + aa Individual Il-1 is genotype AA + Aa + aa Individual Il-7 is genotype AA + Aa + aa Individual I-1 is notype AA + aa Individual lII-5 is genotype AA + Aa + aa Individual IV-3 is genotype AA + Aa + aa For the next question, give the probability as a fraction that is…
Refer to the pedigree below for this question. Individuals who are shaded have an X-inked disorder. Those who are not shaded have the normal phenotype. Let "A" and "a" represent the dominant and recessive alleles, respectively. The disorder represented by the shaded symbol to the normal phenotype. Recessive Dominant A list of possible genotypes is given below. Derermine the appropriate genotype for each individual. Type in the number for the correct answer in the space provided. Do not type arything else in the space. It is ok to use an answer more than one time. 6. 1/2 x^ x^ + 1/2 x^ x 7. 1/4 X x^ +3/4 x^x 8. 3/4 X^ x^ + 1/4 x^ x 9. 1/3 x^ x^ + 2/3 x^ X" 10. 2/3 x^ x^ + 1/3 X^ x* 1. X^ Y 2. X Y 3. X^ xA 4. X^ X 5. X* х The genotype of individual I-1 is The genotype of individual II-5 is The genotype of individual I1-6 is The genotype of individual ill-6 is For the next question, give the probability as a fraction that is simplified to the lowest value. Type your fraction in # format…
A typical pedigree for a family that carries neurofibromatosis is shown below. Note that carriers are not indicated with half-colored shapes in this chart. Use the letter "N" to indicate the dominant neurofibromatosis allele, and the letter "n" for the normal allele. Use the below pedigree chart and your knowledge on how to interpret a pedigree chart to answer questions # 7-9. 1 Nn nn nn 3 nn 7. Is individual #1 most likely homozygous dominant or heterozygous? Explain how you can tell. 8. What is the genotype of individual #2? Explain how you can tell. 9. What is the genotype of individual #3? Explain how you can tell. 2)
If a man with dark skin whose genotype is AaBB reproduces with a woman who has light skin (aaBb), what are the possible skin colors that their children will have? Develop a Punnett square and list the possible genotypes & phenotypes. For your convenience, a table is presented below that shows several possible genotypes & phenotypes: Genotypes Phenotypes AABB Very dark skin AABb or AaBB Dark skin AaBb, AAbb, or aaBB Medium brown skin Aabb or aaBb Light skin aabb Very light skin
Cystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes. Normal allele = F CF mutant allele = f What is the genotype of individual #8?
Suppose two parents, a father with the genotype AaBbccDd and a mother with the genotype aaBbCcDd, want to have children. Assume the loci are inherited independently of each other. Enter your answers as the most simplified fractions (e.g. 1/8 instead of 2/16). What proportion of the offspring are expected to have: The same genotype as the father? The same phenotype as the father? All dominant phenotypes? All recessive phenotypes?
Using the pedigree chart attached: Above is a pedigree for colorblindness. Based on the pedigree, is the disease dominant or recessive and is it sex-linked or autosomal? Why? Furthermore, what is the probability that 18 on this chart is affected but the condition, and what is the probability that 18 is a carrier? Why? Are the probability of being a carrier and an affected individual different? Why?
Refer to the pedigree below for this question. Individuals who are shaded have an X-linked disorder. Those wha are not shaded have the normal phenotype. Let "A" and "a" represent the dominant and recessive alleles, respectively. The disorder represented by the shaded symbol to the normal phenotype. Recessive Daminant A list of possible genotypes is given below. Determine the appropriate genotype for each individual. Type in the number for the correct answer in the space provided. Do not type anything else in the space. It is ok to use an answer more than one time. 1. XАY 6. 1/2 x^ x^ + 1/2 x^ x* 7. 1/4 X^ x* + 3/4 x^ x° 8. 3/4 X^ x^ + 1/4 x^ x 9. 1/3 x^ x* + 2/3 X^ x 10. 2/3 х* х* + 1/3 х^ х 2. X Y 3. ХА ХА 4. X^ X 5. X X The genotype of individual -2 is The genotype of individual -3 is The genotype of individual Il-5 is The genotype of individual II-7 is The genotype of individual lll-3 is
Refer to the pedigree below which shows inheritance for achondroplasia (dwarfism), a dominantly inherited trait (denoted as D), which are the darkened circles and squares. Dwarfism (darkened shapes) are dominantly inherited, while normal height is recessively inherited (hh). Based on the pedigree, what is the correct genotype for individual #II-6? Dominant Autosomal Pedigree 2 II 2 3 II 1 2 3 6 9 10 Dd DD DD or Dd dd
Phenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. Answer the following questions in order and show solutions whenever relevant. a. Indicate the gene notation.b. Derive the expected genotypic and phenotypic ratios.c. If they have a normal child, what is the probability that he or she will be heterozygous?d. If they have three children, what is the probability of having 2 affected children and one normalchild?
Refer to the pedignee below for this question, Individuals who are shaded have a rare autosamal recessive disorder. Those who are not shaded have the dominant phenotype. Let "A" and "a' represent the dominant and recessive alleles, respectively. Fill in the probability functions below to indicate the genotype or probability function far the genotype of each individual. Give all probabilities as fractions that are simplified to the lowest value. Type your fractione in ## format without spaces. For axample, one-half should be typed as 1/2. Place a zero in each space that does not have a number. inst lure Individual 1-3 is genotype 0 AA + 1 Aa + 0 aa Individual Il-4 is genotype 1/3 AA + 2/3 Aa + O aa Individual -5 is genotype AA + Aa + aa Individual Il-1 is genotype AA + Aa + aa Individual Il-5 is genotype AA + Aa + aa Individual Il-6 is genotype AA + Aa + aa Individual III-1 is genotype AA + Aa + aa Individual ill-2 is genotype AA + Aa + aa For the next question, give the probability as…