Please refer to part (a) of Figure 1 included with this quiz. Here, alpha (the angle at the top of the triangular prism) is 42.3 degrees. What is theta (the angle below the horizontal that the ray makes emerging from the prism on the right)?Question 1 options: 28.7 degrees 43.0 degrees 23.9 degrees 14.3 degreesQuestion 2 (5 points) Please refer to part (b) of Figure 1 included with this quiz. Here, theta (the angle the incident ray makes with respect to the vertical) is 33.8 degrees. What is d (the distance between the ray emerging from the bottom of the glass and where the ray would have been if it had continued straight on with no glass to refract it)?Question 2 options: 1.19 m 1.36 m 0.85 m 0.26 mQuestion 3 (5 points) Please refer to part (c) of Figure 1 included with this quiz. Here, the triangle is isosceles, and alpha (the angle at the top of the triangular prism) is 34.7 degrees. What is theta (the angle below the horizontal that the ray makes emerging from the prism on the right)?Question 3 options: 8.8 degrees 4.4 degrees 12.3 degrees 5.3 degreesQuestion 4 (5 points) Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 51.3 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.32 cm, located a distance y= 42.5 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x?Question 4 options: 43.1 cm 53.9 cm 27.0 cm 64.7 cmQuestion 5 (5 points) Please refer again to Figure 2. This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 42.5 degrees, y = 28.6 cm and h = 1.07 cm. What is x now?Question 5 options: 18.8 cm 26.9 cm 13.5 cm 32.3 cm
Please refer to part (a) of Figure 1 included with this quiz. Here, alpha (the angle at the top of the triangular prism) is 42.3 degrees. What is theta (the angle below the horizontal that the ray makes emerging from the prism on the right)?
Question 1 options:
28.7 degrees
43.0 degrees
23.9 degrees
14.3 degrees
Question 2 (5 points)
Please refer to part (b) of Figure 1 included with this quiz. Here, theta (the angle the incident ray makes with respect to the vertical) is 33.8 degrees. What is d (the distance between the ray emerging from the bottom of the glass and where the ray would have been if it had continued straight on with no glass to refract it)?
Question 2 options:
1.19 m
1.36 m
0.85 m
0.26 m
Question 3 (5 points)
Please refer to part (c) of Figure 1 included with this quiz. Here, the triangle is isosceles, and alpha (the angle at the top of the triangular prism) is 34.7 degrees. What is theta (the angle below the horizontal that the ray makes emerging from the prism on the right)?
Question 3 options:
8.8 degrees
4.4 degrees
12.3 degrees
5.3 degrees
Question 4 (5 points)
Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 51.3 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.32 cm, located a distance y= 42.5 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x?
Question 4 options:
43.1 cm
53.9 cm
27.0 cm
64.7 cm
Question 5 (5 points)
Please refer again to Figure 2. This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 42.5 degrees, y = 28.6 cm and h = 1.07 cm. What is x now?
Question 5 options:
18.8 cm
26.9 cm
13.5 cm
32.3 cm
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