Arc Student shown in figure below. Segment BC is an arc of a circle with radius 30.0 cm, and point P is at the center of 3) Calculate the magnetic field (magnitude and direction) at a point P due to a current /= 12.0 A in the wire curvature of the arc. Segment DA is an arc of a circle with radius 20.0 cm, and point P is at its center of curvature. Segments CD and AB are straight lines of length 10.0 cm each. You can use only formulas given on the formula sheets. Everything else needs to be derived. C 20 D T 120° IB M. I de xi Чт B Mo and B Segments DA and CB: B = 14 2 tr : Wire Segment Ak and co ок 蟹 given:- = 30 cm BC BC 20% = 11 TPA 20 cm Mo = BBC Вон 10-6 1.26 x 18-0 T 20 adians Чис - 7 T. MIA Bnet 12 TA Wrong numbers So if will Pace BBC + R 209 x 10 ST out Tt ⠀ Qu e
Arc Student shown in figure below. Segment BC is an arc of a circle with radius 30.0 cm, and point P is at the center of 3) Calculate the magnetic field (magnitude and direction) at a point P due to a current /= 12.0 A in the wire curvature of the arc. Segment DA is an arc of a circle with radius 20.0 cm, and point P is at its center of curvature. Segments CD and AB are straight lines of length 10.0 cm each. You can use only formulas given on the formula sheets. Everything else needs to be derived. C 20 D T 120° IB M. I de xi Чт B Mo and B Segments DA and CB: B = 14 2 tr : Wire Segment Ak and co ок 蟹 given:- = 30 cm BC BC 20% = 11 TPA 20 cm Mo = BBC Вон 10-6 1.26 x 18-0 T 20 adians Чис - 7 T. MIA Bnet 12 TA Wrong numbers So if will Pace BBC + R 209 x 10 ST out Tt ⠀ Qu e
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter24: Magnetic Fields
Section: Chapter Questions
Problem 73A
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