Please predict the product of the following reaction (5). Reaction 5 ملح میں دم کی مكي مام مدمن D H Br H E NaOMe MeOH B H ?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Please predict the product of the following reaction (5).**

**Reaction 5:**

The given chemical reaction shows an organic compound with a bromine (Br) substituent reacting with sodium methoxide (NaOMe) in methanol (MeOH). 

The reactant structure:
- A bicyclic compound with a bromine atom and two phenyl rings. 
- One hydrogen atom is shown with a wedge bond, indicating its stereochemistry.

**Possible Products:**

The diagram presents eight potential products labeled A through H. Each is a structural variation of the initial reactant:

- **A:** Features an ether linkage with two phenyl rings attached. The stereochemistry of substituents is maintained, but the bromine is replaced with an -OCH3 group.
- **B:** Similar to A, but differs in the arrangement of phenyl groups and the stereochemistry of the methyl group.
- **C:** A structure with a rearranged double bond and no ether linkage, having a single phenyl group attached.
- **D:** Maintains the ring structure with a rearranged configuration and one phenyl ring.
- **E:** Features a different stereochemical configuration with a rearranged double bond and phenyl group.
- **F:** Shows rearrangement with a simplified bicyclic structure and one phenyl ring.
- **G:** Contains an ether linkage similar to A and B but differs in stereochemistry and phenyl placement.
- **H:** Simplifies to a bicyclic structure with phenyl modification, lacking the ether linkage.

Students are expected to determine the most likely product of the reaction based on the provided conditions and mechanistic understanding.
Transcribed Image Text:**Please predict the product of the following reaction (5).** **Reaction 5:** The given chemical reaction shows an organic compound with a bromine (Br) substituent reacting with sodium methoxide (NaOMe) in methanol (MeOH). The reactant structure: - A bicyclic compound with a bromine atom and two phenyl rings. - One hydrogen atom is shown with a wedge bond, indicating its stereochemistry. **Possible Products:** The diagram presents eight potential products labeled A through H. Each is a structural variation of the initial reactant: - **A:** Features an ether linkage with two phenyl rings attached. The stereochemistry of substituents is maintained, but the bromine is replaced with an -OCH3 group. - **B:** Similar to A, but differs in the arrangement of phenyl groups and the stereochemistry of the methyl group. - **C:** A structure with a rearranged double bond and no ether linkage, having a single phenyl group attached. - **D:** Maintains the ring structure with a rearranged configuration and one phenyl ring. - **E:** Features a different stereochemical configuration with a rearranged double bond and phenyl group. - **F:** Shows rearrangement with a simplified bicyclic structure and one phenyl ring. - **G:** Contains an ether linkage similar to A and B but differs in stereochemistry and phenyl placement. - **H:** Simplifies to a bicyclic structure with phenyl modification, lacking the ether linkage. Students are expected to determine the most likely product of the reaction based on the provided conditions and mechanistic understanding.
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