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Pinacol is to pinacolone under acidic conditon. What are the oxidation numbers on carthon with in pinacol and pinacolone, respectively? H3C CH, HO 6M H,SO, HO, H,C H,c CH, H,C CH, pinacol pinacolone OA reduced, +1,0 O 0. oxidized, +1, +2 OC oxidized, 0, +2 O D, axidized, +1, 0 O E. axidized, +2, +1

Pinacol is to pinacolone under acidic conditon. What are the oxidation numbers on carthon with in pinacol and pinacolone, respectively? H3C CH, HO 6M H,SO, HO, H,C H,c CH, H,C CH, pinacol pinacolone OA reduced, +1,0 O 0. oxidized, +1, +2 OC oxidized, 0, +2 O D, axidized, +1, 0 O E. axidized, +2, +1

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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QUESTION 24 Pinacol is to pinacolone under acidic conditon. What are the oxidation numbers on carthon with in pinacol and pinacolone, respectively H3C CH, HO OH 6 M H,SO, H3C. H,C CH, H,c CH, CH, pinacol pinacolone OA reduced +1, 0 O B. oxidized, +1, +2 OG oxidized, 0, +2 O D. oxidized, +1, 0 OE. oxidized,+2. +1 QUESTION 25 Which of the following equations accurately represents the total vapor pressure above a boiling immiscible mixture of 2 moles af citral (P= 15 Torr) and 6 moles of water (P 745 Tor) O A. None of the answers O B. PT = (0 33)(15) + (0 67)(745) OC.Pr= (0.75)(15)+(0.25)(745) O D. PT = (2)(15) + (6)(745) !! OE PT = (0 25X15) + (0.75)(745)
Transcribed Image Text:QUESTION 24 Pinacol is to pinacolone under acidic conditon. What are the oxidation numbers on carthon with in pinacol and pinacolone, respectively H3C CH, HO OH 6 M H,SO, H3C. H,C CH, H,c CH, CH, pinacol pinacolone OA reduced +1, 0 O B. oxidized, +1, +2 OG oxidized, 0, +2 O D. oxidized, +1, 0 OE. oxidized,+2. +1 QUESTION 25 Which of the following equations accurately represents the total vapor pressure above a boiling immiscible mixture of 2 moles af citral (P= 15 Torr) and 6 moles of water (P 745 Tor) O A. None of the answers O B. PT = (0 33)(15) + (0 67)(745) OC.Pr= (0.75)(15)+(0.25)(745) O D. PT = (2)(15) + (6)(745) !! OE PT = (0 25X15) + (0.75)(745)
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