ExampleThe following test data were taken on a 7.5-hp, four-pole, 208-V, 60-Hz,Y-connected IM having a rated current of 28 A.DC Test:Voc = 13.6 VNo-load Test:V = 208 V| = 8.17 ALocked-rotor Test:Ipc = 28.0 Af= 60 HzPn= 420 WV = 25 V| = 27.9 Af = 15 HzPin = 920 W(a) Sketch the per-phase equivalent circuit of this motor.(b) Find the slip at pull-out torque, and find the value of the pull-outtorque.E NOTESCOMMENTS

An induction motor is an asynchronous motor in which the stator winding is connected to a…

Answered: Pin = 920 W n the per-phase equivalent…

Engineering

Electrical Engineering

Pin = 920 W n the per-phase equivalent circuit he slip at pull-out torque, and find e.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter12: Power System Controls

Section: Chapter Questions

Problem 12.4P

See similar textbooks

Similar questions

L-1). The 3-phase wound-rotor induction motor has .... . a) high starting torque b) low starting current c) both "a" and "b" d) neither "a" nor "b" L-2). The 3-phase wound-rotor induction.........a) motor has a wire wound rotor b) motor's rotor can be connected to an external resistive load by way of slip rings and brushes c) motor requires more maintenance than the 3-phase squirrel-cage induction motor d) all of the above L-3). The 3-phase wound-rotor induction motor's rotor circuit's resistance should be adjusted so it is__________ during starting. a) low b) high c) either "a" or "b" d) neither "a" nor "b" L-4). Will a 3-phase wound-rotor induction motor start with no external circuit connected to its rotor leads? a) yes b) no
can someone help me out with this question 5 and pls explain clearly, tq
I want to represent each point on the graph paper with its corresponding scale written alongside it.
The armature circuit of a free excited direct current motor with a nominal voltage of 600 V is fed from an adjusted direct voltage source. The excitation circuit is also powered from a regulated voltage source. It is used in an application that requires motor speed adjustment. The speed of the motor at the nominal armature voltage was measured as 1600 rpm. All losses of the motor and voltage source and the effect of armature reaction are neglected. It is accepted that the engine is not saturated.Answer the questions below.a) Draw the armature and excitation circuit of the motor and write the formulas for the equivalent circuit.b) If the load moment of the motor at the nominal armature voltage is 420 Nm, then calculate the armature current and the input power of the motor.c) If the armature voltage of the motor is kept constant at 600 V and the excitation current is decreased until the speed reaches 4000 rpm, then calculate the shaft moment. Show this working area on the M = f (W) axis.
9-In a the shunt field winding is connected in parallel with the armature winding only. Ish Series . Field EJR Shunt Rsh Rse Field 10-The consist of and 11- E = (V – IaRa ) then N = LOAD
None
Speed control of a 140 V, 1.68 kW DC motor single phase thyristor full wave AC-DC It is made by the converter. AA supply voltage 220 V (rms) Is 50. In the converter It is assumed that there is no loss. The armature resistance of the DC motor is = 0.417 Q. Very a large inductance is connected in series with the motor. The motor voltage constant is = 0.0964 V/rpm. The motor can be considered as a permanent magnet DC. According to this, a) Draw the driver (converter-motor) power circuit. b) Calculate the nominal current of the motor. c) Supply voltage, supply current, converter output voltage for ignition angle a = 30 ° and Draw the waveforms for the converter output current. d) = 950 rpm and for nominal current, d1) The firing angle of the converter, d2) Effective value of supply and thyristor current, d3) Supply power factor, calculate.
Two identical 3-phase, 500-V induction machines are mechanically coupled for a back-to-back test. One machine is motoring from a 500-V, 50-Hz supply and the other is generating on to a 3-phase, 500-V synchronous machine for which the fre- quency can be controlled. It is required to run the motoring induction mạchine at 40 hp. Neglecting the slight change in the generating machine parameters due to oper- ating at a reduced frequency, estimate the rating of the synchronous machine for this duty and the frequency at which it must be run. Line input readings for each machine No load 500 V 8.5 A 1-6 kW Locked rotor 100 V 30 A 1-6 kW Friction and windage loss per machine 0-8 kW. R = R2'
A freewheeling DC motor is driven with 1000 rpm and a nominal load torque of 80Nm. The field circuit resistance is 200 and the armature circuit resistance is 0.2 O. The field coils are fed with a zero degree transmission angle through a single-phase fully controlled converter connected to a single-phase 240V source. The armature circuit is fed from a single phase 400V source through another fully controlled converter. Magnetic saturation has been neglected, the motor constant is given as 0.8 V - s / A - rad. Assuming that there is no fluctuation in armature and field current, find the control angle of the converter feeding the armature at nominal load. If you want to leave the question blank, click again on the option you marked.
Kindly solve what is ask with complete solution and circuit diagram so that I can understand. I want a handwritten solution and write the givens. Thank you very much ma'am/sir..
Q4/B/ What are the principal characteristics of a series DC motor? What are its uses? Core Mc
Q9) Specifications for a PM DC motor are as follows: • electrical constant (KEMF) = 0.014V/rpm • and armature resistance=202. What are the motor's no-load speed (w), stall torque, and maximum power for an applied voltage of 12 V? ((rad/s-0.105 rpm)) V ww000 RA IA LA Veur TM 18.0 JM T₂