Phosphoric acid is a triprotic acid (Kal = 6.9 × 10-3, Ka2 = 6.2 x 10-8, and Ka3 = 4.8 x 10-13). To find the pH of a buffer composed of H, PO, (aq) and HPO¯(aq), which pKa value should be used in the Henderson-Hasselbalch equation? pKal = 2.16 pKa2 = 7.21 pKa3 = 12.32 Calculate the pH of a buffer solution obtained by dissolving 16.0 g of KH,PO,(s) and 32.0 g of Na, HPO, (s) in water and then diluting to 1.00 L. pH =

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### pH Calculation of a Buffer Solution

**Phosphoric acid is a triprotic acid**, defined by its three dissociation constants:
- \( K_{a1} = 6.9 \times 10^{-3} \)
- \( K_{a2} = 6.2 \times 10^{-8} \)
- \( K_{a3} = 4.8 \times 10^{-13} \)

#### Determining the Correct \( \text{p}K_a \) for the Buffer Solution
To find the pH of a buffer that is composed of \( \text{H}_2\text{PO}_4^- \) (aq) and \( \text{HPO}_4^{2-} \) (aq), which \( \text{p}K_a \) value should be used in the Henderson-Hasselbalch equation? The options are:
- \( \text{p}K_{a1} = 2.16 \)
- \( \text{p}K_{a2} = 7.21 \)
- \( \text{p}K_{a3} = 12.32 \)

Since we are considering the buffer system involving \( \text{H}_2\text{PO}_4^- \) and \( \text{HPO}_4^{2-} \), the appropriate \( \text{p}K_a \) value to use is:
\[ \text{p}K_{a2} = 7.21 \]

#### Buffer Solution pH Calculation
To calculate the pH of a buffer solution obtained by:
- Dissolving **16.0 g of \( \text{KH}_2\text{PO}_4 \) (s)** and 
- **32.0 g of \( \text{Na}_2\text{HPO}_4 \) (s)**

the mixture is then diluted to **1.00 L**. 

Use the following open-ended form to determine the pH:
\[ \text{pH} = \]

[Include the Henderson-Hasselbalch equation and any necessary steps here to guide students through the calculation process.]

### Henderson-Hasselbalch Equation:
\[ \text{pH} = \text{p}K_a + \log \left( \frac{[\text{A}^-]}{[\text{
Transcribed Image Text:### pH Calculation of a Buffer Solution **Phosphoric acid is a triprotic acid**, defined by its three dissociation constants: - \( K_{a1} = 6.9 \times 10^{-3} \) - \( K_{a2} = 6.2 \times 10^{-8} \) - \( K_{a3} = 4.8 \times 10^{-13} \) #### Determining the Correct \( \text{p}K_a \) for the Buffer Solution To find the pH of a buffer that is composed of \( \text{H}_2\text{PO}_4^- \) (aq) and \( \text{HPO}_4^{2-} \) (aq), which \( \text{p}K_a \) value should be used in the Henderson-Hasselbalch equation? The options are: - \( \text{p}K_{a1} = 2.16 \) - \( \text{p}K_{a2} = 7.21 \) - \( \text{p}K_{a3} = 12.32 \) Since we are considering the buffer system involving \( \text{H}_2\text{PO}_4^- \) and \( \text{HPO}_4^{2-} \), the appropriate \( \text{p}K_a \) value to use is: \[ \text{p}K_{a2} = 7.21 \] #### Buffer Solution pH Calculation To calculate the pH of a buffer solution obtained by: - Dissolving **16.0 g of \( \text{KH}_2\text{PO}_4 \) (s)** and - **32.0 g of \( \text{Na}_2\text{HPO}_4 \) (s)** the mixture is then diluted to **1.00 L**. Use the following open-ended form to determine the pH: \[ \text{pH} = \] [Include the Henderson-Hasselbalch equation and any necessary steps here to guide students through the calculation process.] ### Henderson-Hasselbalch Equation: \[ \text{pH} = \text{p}K_a + \log \left( \frac{[\text{A}^-]}{[\text{
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