Perform the test of hypothesis on the following scenarios. The minimum wage earners of the National Capital Region are believed to be receiving less than Php 5,000.00 per day. The CEO of a large supermarket chain in the region is claiming to be paying its contractual higher than the minimum daily wage rate of Php 500.00 To check on this claim, a labour union leader obtained a random sample of 144 contractual employees from this supermarket chain. The survey of their daily wage earnings resulted to an average wage of Php 510.00 per day with standard deviation of Php 100.00. The daily wage of the region is assumed to follow a distribution with unknown population variance. Perform a test of hypothesis at 5% level of significance to help the labour union leader make an empirical based conclusion on the CEO's claim. Note: pls follow the steps in the photo attached

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Perform the test of hypothesis on the following scenarios. The minimum wage earners of the National Capital Region are believed to be receiving less than Php 5,000.00 per day. The CEO of a large supermarket chain in the region is claiming to be paying its contractual higher than the minimum daily wage rate of Php 500.00 To check on this claim, a labour union leader obtained a random sample of 144 contractual employees from this supermarket chain. The survey of their daily wage earnings resulted to an average wage of Php 510.00 per day with standard deviation of Php 100.00. The daily wage of the region is assumed to follow a distribution with unknown population variance. Perform a test of hypothesis at 5% level of significance to help the labour union leader make an empirical based conclusion on the CEO's claim. Note: pls follow the steps in the photo attached
Please follow the steps
Solution:
Given:
Method
n
x (Sample Mean)
s (Sample SD)
Proposed
n₁ = 15
S₁ = 4.98
X₁ = 24.27
X₂ = 20.93
Existing
n₂ = 15
$2 = 155.05
*** Compute first the mean and standard deviation using the given data in the
problem. (Recall our previous lesson on how to get the mean and standard deviation).
Step 1: Form the null and alternative hypothesis.
Ho: The E-learning method is as effective as the traditional method of teaching; or μ₁ =
μ₂.
Ha: The E-learning method is more effective than the traditional method of teaching; or
με > Ma.
Step 2: A one-tailed t-test must be used since n<30 and the given a = 5%. The
degree of freedom is df = n₁ + n2-2=15+15-2 = 28
Step 3: A one-tailed test at a = 5% would give c = 1.701 using the t-table with a
degree of freedom equals to 28.
71Page
Lear IvIUuure лини
Step 4: Computing for the t-score, we have:
t=*= √n
t = 12-10√12 = 1.732
0.4
Step 5: Since t < c, or the computed t-score is in the region of Ho, we accept Ho.
Conclusion: There is no significant difference between the mean serum of the
sample group and that of the population.
1 tonahing method is more effective
Transcribed Image Text:Please follow the steps Solution: Given: Method n x (Sample Mean) s (Sample SD) Proposed n₁ = 15 S₁ = 4.98 X₁ = 24.27 X₂ = 20.93 Existing n₂ = 15 $2 = 155.05 *** Compute first the mean and standard deviation using the given data in the problem. (Recall our previous lesson on how to get the mean and standard deviation). Step 1: Form the null and alternative hypothesis. Ho: The E-learning method is as effective as the traditional method of teaching; or μ₁ = μ₂. Ha: The E-learning method is more effective than the traditional method of teaching; or με > Ma. Step 2: A one-tailed t-test must be used since n<30 and the given a = 5%. The degree of freedom is df = n₁ + n2-2=15+15-2 = 28 Step 3: A one-tailed test at a = 5% would give c = 1.701 using the t-table with a degree of freedom equals to 28. 71Page Lear IvIUuure лини Step 4: Computing for the t-score, we have: t=*= √n t = 12-10√12 = 1.732 0.4 Step 5: Since t < c, or the computed t-score is in the region of Ho, we accept Ho. Conclusion: There is no significant difference between the mean serum of the sample group and that of the population. 1 tonahing method is more effective
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