passonly?Q 2(b)[20 Marks]The deflection temperature under load for two different types of plastic pipe is beinginvestigated. Two random samples with size 8 and 9 pipe specimens are tested, andthe deflection temperature observed are reported here (in °C).Type 1Type 225 30 15 19 30 24 10 1220 22 15 8 25 12 14 109Assume that the deflection temperature follows a normal distribution.(i)(ii)Find estimates of the mean and the standard deviation of deflectiontemperature for each type of plastic pipe.(iii)Using your answers from part (i), find the probability that the deflectiontemperature for a piece of Type 1 plastic pipe is less than 25°C.Using your answers from part (i), find the temperature at which 75% ofType 2 plastic pipes will deform.Note: Give your answers to 2 decimal places in this question.%4+Q Search&*hpTAmyhpA12insprt scdeletef10DDIf12ENGGA

Given Data:Type 1: [25, 30, 15, 19, 30, 24, 10, 12]Type 2: [20, 22, 15, 8, 25, 12, 14, 10, 9] Part…

Answered: pass only? Q 2(b) [20 Marks] The…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Automobile Parts: An important manufacturing process produces cylindrical component parts for the automotive industry. It is important that the process produce parts having a mean diameter of 5.0 millimeters. The engineer involved conjectures that the population mean is 5.0 millimeters. An experiment is conducted in which 100 parts produced by the process are selected randomly and the diameter measured on each. It is known that the population standard deviation is σ = 0.1 millimeter. The experiment indicates a sample average diameter of x = 5.027 millimeters. Does this sample information appear to support or refute the engineer's conjecture?
The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use a = 0.01 and assume normality. n- 40, Σd- 207, Σα? = 6199 (a) Find t. (Give your answer correct to two decimal places.) (ii) Find the p-value. (Give your answer correct to four decimal places.) (b) State the appropriate conclusion. O Reject the null hypothesis, there is significant evidence that the coating is beneficial. Reject the null hypothesis, there is not significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is not significant evidence that the coating is beneficial.
Current Attempt in Progress In the manufacture of electroluminescent lamps, several different layers of ink are deposited onto a plastic substrate. The thickness of these layers is critical if specifications regarding the final color and intensity of light of the lamp are to be met. Let X and Y denote the thickness of two different layers of ink. It is known that X is normally distributed with a mean of 0.1 millimeter and a standard deviation of 0.00031 millimeter, and Y is also normally distributed with a mean of 0.23 millimeter and a standard deviation of 0.00017 millimeter. The value of r for these variables is equal to zero. specifications call for a lamp to have a thickness of the ink corresponding to x in the range of 0.099535 to 0.100465 and Yin the range of 0.22966 to 0.23034 millimeter. What is the probability that a randomly selected lamp will conform to specifications? Round your answer to four decimal places (e.g. 98.7654).
TF.17 The average number of UHD TVs sold daily at a Best Buy store is known to be 28 and approximately normally distributed. A random sample of 21 days shows sample mean x̄ = 31 with standard deviation s = 7.7. Test the hypothesis Ho : μ = 28 against Ha : μ ≠ 28 at α = 0.10 and at α = 0.05 levels of significance. Use t-distribution.
Find the Q1, Q3 and IQR of the 1% hydrogen peroxide
A normal distribution has μ = 30 and σ = 5. (a) Find the z score corresponding to x = 25. (Enter an exact number.) (b) Find the z score corresponding to x = 44. (Enter a number.) (c) Find the raw score corresponding to z = −3. (Enter an exact number.) (d) Find the raw score corresponding to z = 1.5. (Enter a number.)
The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure. (a) What is the minimum UGPA that would still place a student in the top 10% of UGPAs? (b) Between what two values does the middle 50% of the UGPAs lie? 3.4042.8Grade point average μ=3.40 σ=0.17 x A normal curve labeled mu = 3.40 and sigma = 0.17 is over a horizontal x-axis labeled Grade point average from 2.8 to 4 in increments of 0.3 and is centered on 3.40. (a) The minimum UGPA that would still place a student in the top 10% of UGPAs is nothing. (Round to two decimal places as needed.) (b) The middle 50% of UGPAs lies between nothing on the low end and nothing on the high end. (Round to two decimal places as needed.)
Consider the normal distribution represented by the normal curve in the figure to the right. (Assume the two labeled values are equidistant from the mean.) Complete parts (a) and (b) below. 95% of the data 73.2 cm 96.8 cm (a) Find the mean μ and standard deviation σ of the distribution. με cm (Simplify your answer.) σ = cm (Simplify your answer.) (b) Find the first quartile Q1 and the third quartile Q3 of the distribution. ༠ ༤ cm (Round to the nearest tenth as needed.) Q3≈ cm (Round to the nearest tenth as needed.)
roblem 1 If the population parameters are μ = 7 and σ = 1: a) Compute the z score for the lowest (x-4) and highest grade (x=10). (15 pts) -3 b) Compute the proportion of the normal distribution corresponds to z-score values greater than the highest grade. (10 pts) 7 = 7 0 σ = I X = 10 3 3.00
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The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure. (a) What is the minimum UGPA that would still place a student in the top 15% of UGPAs? (b) Between what two values does the middle 50% of the UGPAs lie? 3.3042.6Grade point average μ=3.30 σ=0.16 x A normal curve labeled mu = 3.30 and sigma = 0.16 is over a horizontal x-axis labeled Grade point average from 2.6 to 4 in increments of 0.35 and is centered on 3.30. (a) The minimum UGPA that would still place a student in the top 15% of UGPAs is enter your response here. (Round to two decimal places as needed.)

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