The undergraduate grade point averages​ (UGPA) of students taking an admissions test in a recent year can be approximated by a normal​ distribution, as shown in the figure.   ​(a) What is the minimum UGPA that would still place a student in the top 10​% of​ UGPAs? ​(b) Between what two values does the middle 50​% of the UGPAs​ lie?               3.2442.48Grade point average μ=3.24 σ=0.17 x         A normal curve labeled mu = 3.24 and sigma = 0.17 is over a horizontal x-axis labeled Grade point average from 2.48 to 4 in increments of 0.38 and is centered on 3.24. ​(a) The minimum UGPA that would still place a student in the top 10​% of UGPAs is nothing. ​(Round to two decimal places as​ needed.) ​(b) The middle 50​% of UGPAs lies between nothing on the low end and nothing on the high end. ​(Round to two decimal places as​ needed.)

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The undergraduate grade point averages​ (UGPA) of students taking an admissions test in a recent year can be approximated by a normal​ distribution, as shown in the figure.
 
​(a) What is the minimum UGPA that would still place a student in the top
10​%
of​ UGPAs?
​(b) Between what two values does the middle
50​%
of the UGPAs​ lie?
 
 
 
 
 
 
 
3.2442.48Grade point average
μ=3.24
σ=0.17
x
 
  •  
  •  
  •  
A normal curve labeled mu = 3.24 and sigma = 0.17 is over a horizontal x-axis labeled Grade point average from 2.48 to 4 in increments of 0.38 and is centered on 3.24.
​(a) The minimum UGPA that would still place a student in the top
10​%
of UGPAs is
nothing.
​(Round to two decimal places as​ needed.)
​(b) The middle
50​%
of UGPAs lies between
nothing
on the low end and
nothing
on the high end.
​(Round to two decimal places as​ needed.)
Expert Solution
Step 1

Let;

X = Undergraduate grade point averages​ (UGPA) of students

X~Normal(μ=3.24, σ=0.17)

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