The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure. (a) What is the minimum UGPA that would still place a student in the top 10% of UGPAs?(b) Between what two values does the middle 50% of the UGPAs lie? 3.4042.8Grade point averageμ=3.40σ=0.17x A normal curve labeled mu = 3.40 and sigma = 0.17 is over a horizontal x-axis labeled Grade point average from 2.8 to 4 in increments of 0.3 and is centered on 3.40. (a) The minimum UGPA that would still place a student in the top 10% of UGPAs is nothing.(Round to two decimal places as needed.)(b) The middle 50% of UGPAs lies between nothing on the low end and nothing on the high end.(Round to two decimal places as needed.)

Answered: 3.4042.8Grade point average μ=3.40…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure.

(a) What is the minimum UGPA that would still place a student in the top 10% of UGPAs?

(b) Between what two values does the middle 50% of the UGPAs lie?

3.4042.8Grade point average

μ=3.40

σ=0.17

A normal curve labeled mu = 3.40 and sigma = 0.17 is over a horizontal x-axis labeled Grade point average from 2.8 to 4 in increments of 0.3 and is centered on 3.40.

(a) The minimum UGPA that would still place a student in the top 10% of UGPAs is nothing.

(Round to two decimal places as needed.)

(b) The middle 50% of UGPAs lies between nothing on the low end and nothing on the high end.

(Round to two decimal places as needed.)

Expert Solution

Step 1

A normal curve labeled mu = 3.40 and sigma = 0.17 is over a horizontal x-axis labeled Grade point average from 2.8 to 4 in increments of 0.3 and is centered on 3.40.