Part V. Graphical AnalysisInstruction. You are given a null hypothesis and three confidence intervals that represent threesamplings. D etermine whether each confidence interval indicates that you should reject the nullhypothesis. Explain your reasoning.1.Ho PS0.20017 0.18 0.19 0,20 0.21 022 023(a)(b)

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A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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You are conducting a study to see if the proportion of men over the age of 50 who regularly have their prostate examined is significantly less than 0.34. A random sample of 720 men over the age of 50 found that 206 have their prostate regularly examined. Do the sample data provide convincing evidence to support the claim? Test the relevant hypotheses using a 5% level of significance. Ho: P=0.34 Ha: P<0.34 test statistic =-3.0525 Critical-value= ?
Test the claim that the mean GPA of night students is significantly different than 2 at the 0.05 significance level. The null and alternative hypothesis would be: Ho:p > 0.5 Ho:µ 2 Ho:p= 0.5 Ho:µ = 2 Ho:p 2 H1:µ 0.5 The test is: two-tailed right-tailed left-tailed Based on a sample of 45 people, the sample mean GPA was 1.99 with a standard deviation of 0.08 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is μ=14.00Mbps. The sample size is n=25and the test statistic is t=−1.313.
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Test the claim that the mean GPA of night students is smaller than 2.5 at the 0.10 significance level. The null and alternative hypothesis would be: Но:р — 0.625 Но:р 0.625 Но:> 2.5 Но: д %3 2.5 Но: н 0.625 Н:р 2.5 The test is: right-tailed two-tailed left-tailed Based on a sample of 55 people, the sample mean GPA was 2.47 with a standard deviation of 0.03 The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Match the hypothesis to the situation. Hypothesis: 1. Ho: p1=p2 2. Ho: p= .73 3. Ho: = 0 4. Ho: 11 = ₂ 5. Ho: =.73 Two sample mean, independent samples Two sample mean, dependent samples One sample mean One sample proportion Two sample proportion o [Choose | [Choose ] Hypothesis 3 None of the hypothesis Hypothesis 4 Hypothesis 2 Hypothesis 5 Hypothesis 1 € A ► n 3
C Calculate the upper 99% confidence interval for the population mean. (round to the nearest tenth) DATA: F4 Je 4 BEBE CIX n= X= 9. - F5 1% Click Save and Submit to save and submit. Click Save All Answers to save all answers. - 87 MOOTTO 46 141 T (₁) F6 A 6 F7 LCD/C & 7 SONY F8 7 J ** 8 F9 (81 (( 9 5 K WEB F10 9 Ⓡ One Touch Web Access Without Be C F11 0 6 L 1 Save All Answers P F12 Save * Num Lk Scr Lk Enter
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You randomly select and measure the contents of 10 bottles of cough syrup. The results (in fluid ounces) are shown to the right. 4.216, 4.293, 4.255, 4.241, 4.187, 4.247, 4.264, 4.243, 4.226, 4.233 Assume the sample is taken from a normally distributed population. Construct 90% confidence intervals for (a) the population variance sigma squared and (b) the population standard deviation sigma. Interpret the results. (a) The confidence interval for the population variance is ______.(Round to six decimal places as needed.) (b) The confidence interval for the population standard deviation is ______.(Round to four decimal places as needed.)
Getting enough sleep. 400 students were randomly sampled from a large university, and 289 said they did not get enough sleep. Conduct a hypothesis test to check whether this represents a statistically significant difference from 50%, and use a significance level of 0.01. NB: Use confidence interval
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho: M = μF Ho: PM = PF H₁ μM μF H₁:PM > PF The test is: left-tailed right-tailed two-tailed Based on a sample of 60 men, 30% owned cats Based on a sample of 40 women, 45% owned cats The test statistic is: Ho: PM = PF H₁: PM μF (to 2 decimals) (to 2 decimals) Ho: PM = PF Ho: M = μF H₁:PM ‡ PF H₁: μM < MF
II

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