Test the claim that the mean GPA of night students is significantly different than 2 at the 0.05 significance level. The null and alternative hypothesis would be: Ho:p 2 0.5 Ho:µ <2 Ho:µ > 2 Ho:p = 0.5 Ho:µ= 2 Ho:p< 0.5 H:p< 0.5 H1:µ > 2 H1:µ< 2 H1:p+0.5 H:µ+2 H:p> 0.5 The test is: two-tailed right-tailed left-tailed Based on a sample of 45 people, the sample mean GPA was 1.99 with a standard deviation of 0.08 The test statistic is: (to 2 decimals) The p-value is: |(to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis

Test the claim that the mean GPA of night students is significantly different than 2 at the 0.05 significance level. The null and alternative hypothesis would be: Ho:p 2 0.5 Ho:µ <2 Ho:µ > 2 Ho:p = 0.5 Ho:µ= 2 Ho:p< 0.5 H:p< 0.5 H1:µ > 2 H1:µ< 2 H1:p+0.5 H:µ+2 H:p> 0.5 The test is: two-tailed right-tailed left-tailed Based on a sample of 45 people, the sample mean GPA was 1.99 with a standard deviation of 0.08 The test statistic is: (to 2 decimals) The p-value is: |(to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis

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Description: Test the claim that the mean GPA of night students is significantly different than 2 at the 0.05significance level.The null and alternative hypothesis would be:Ho:p > 0.5 Ho:µ 2 Ho:p= 0.5 Ho:µ = 2 Ho:p 2 H1:µ < 2 Hị:p +

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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An RA at the University of Baltimore has concluded that the difference between the mean GPA scores of Senior and junior is statistically significant, when in fact the null hypothesis of no difference is true. What type of error has he committed?
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Test the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 The test is: right-tailed left-tailed two-tailed Based on a sample of 20 people, 84% owned catsThe test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
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