A well-known brokerage firm executive claimed that 10% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 800 people, 18% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 10% at the 0.01 significance level. The null and alternative hypothesis would be: Ho: µ < 0.1 Ho:p = 0.1 Ho:p > 0.1 Ho:µ > 0.1 Họ:µ = 0.1 Ho:p< 0.1 H1: µ > 0.1 H1:p + 0.1 H1:p < 0.1 H1:µ < 0.1 H1:µ + 0.1 H1:p > 0.1 %3D The test is: right-tailed left-tailed two-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

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A well-known brokerage firm executive claimed that 10% of investors are currently confident of meeting their
investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample
of 800 people, 18% of them said they are confident of meeting their goals.
Test the claim that the proportion of people who are confident is larger than 10% at the 0.01 significance
level.
The null and alternative hypothesis would be:
0.1 Ho:p > 0.1 Ho:µ > 0.1 Họ:µ = 0.1 Ho:p < 0.1
Ho: µ < 0.1 Ho:p
H1: µ > 0.1 H1:p # 0.1 H1:p < 0.1 H1: µ < 0.1 H1:u + 0.1 H1:p > 0.1
%3D
The test is:
right-tailed left-tailed two-tailed
The test statistic is:
(to 3 decimals)
The p-value is:
(to 4 decimals)
Based on this we:
O Reject the null hypothesis
Fail to reject the null hypothesis
Transcribed Image Text:A well-known brokerage firm executive claimed that 10% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 800 people, 18% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 10% at the 0.01 significance level. The null and alternative hypothesis would be: 0.1 Ho:p > 0.1 Ho:µ > 0.1 Họ:µ = 0.1 Ho:p < 0.1 Ho: µ < 0.1 Ho:p H1: µ > 0.1 H1:p # 0.1 H1:p < 0.1 H1: µ < 0.1 H1:u + 0.1 H1:p > 0.1 %3D The test is: right-tailed left-tailed two-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: O Reject the null hypothesis Fail to reject the null hypothesis
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