n =14 s = 20 The null hypothesis is to be tested at the 5% level of significance. The critical value(s) from the table is(are) _____.
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n =14 s = 20
The null hypothesis is to be tested at the 5% level of significance. The critical value(s) from the table is(are) _____.
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- Observations from The null hypothesis is Ho: H1 = H, and the alternative hypothesis is as specified. The provided data are from a simple random paired sample from the two populations under consideration. Use the paired t-test to perform the required hypothesis test at the 10% significance level. Pair Population 1 Population 2 24 20 Hai Hy> H2 2 9 10 20 19 E Click the icon to view the t-table. 4. 13 8 5 8 14 14 7 10 15 8 22 28 Find the test statistic. Use population 1- population 2 as the difference. t=| (Round to three decimal places as needed.)You are conducting a multinomial hypothesis test for the claim that the 4 categories occur with the following frequencies:HoHo : pA=0.15p; pB=0.3; pC=0.15; pD=0.4pComplete the table. Category ObservedFrequency ExpectedFrequency SquaredResidual A 16 B 33 C 16 D 43 What is the chi-square test-statistic for this data?χ2=Report all answers accurate to three decimal places.VERY IMPORTANT NOTE: Answers are reported to 3 decimal places, but you should use all the decimal places to calculate the final chi-square test statistic...DO NOT use the rounded number you report in the table.A coin-operated drink machine was designed to discharge a mean of 9 ounces of coffee per cup. Suppose that we want to carry out a hypothesis test to see if the true mean discharge differs from 9. State the null hypothesis H, and the alternative hypothesis H, that we would use for this test. Ho: 0 H1: 0 OsO O>o O20 ?
- Suppose you reject the null hypothesis H0: μ = 58. It turns out the population mean is actually equal to 55. You have made Group of answer choices Type I and Type II errors a Type II error a Type I error the correct decisionSuppose there is a claim that a certain population has a mean, H, that is different than 5. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.10 level of significance. To start this test, you write the null hypothesis, Ho, and the alternative hypothesis, H1, as follows. Hg: u= 5 H1: u=5 Suppose you also know the following information. The value of the test statistic based on the sample is 1.506 (rounded to 3 decimal places). The p-value is 0.132 (rounded to 3 decimal places). (a) Complete the steps below for this hypothesis test. Standard Normal Distribution 04 Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed 0.3+ Step 2: Enter the test statistic. (Round to 3 decimal places.) 0.2 Step 3: Shade the area represented by the p-value. 0.1+ Step 4: Enter the p-value. (Round to 3 decimal places.) ? (b) Based on your answer to part (a), which statement below is true? Since the p-value is less…Scenario: 200 people were asked, “Who is your favorite superhero?” Below are the data. Test the null hypothesis that the population frequencies for each category are equal. α= .05. Iron Man Black Panther Wonder Woman Spiderman fo = 40 fo = 60 fo =55 fo = 45 fe = fe = fe = fe = What is the correct result based on the data?
- B. Calculate the value of the test statistic. χ2=____ C. Use technology to determine the P-value for the test statistic. The P-value is______ D. What is the correct conclusion at the α=0.10 level of significance? Since the P-value is(greater or less)than the level of significance. (Do not reject or reject) the null hypothesis. There (is or is not) sufficient evidence to conclude that the standard deviation of heights of major-league baseball players is less than 2.4 inches at the 0.10 level of significance. 8/ a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? The test statistic, t, The P-value is State the conclusion for the test. A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. D. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights…Answer these questions A, B, C and D question
- The results of a hypothesis test are reported as follows in a scientific report: t(38) = -3.13, p < .05. Based on this information, which statement below is not correct? Group of answer choices The sample size was n = 39. The conclusion reached by the researcher was to reject the null hypothesis. The sample mean was greater than the hypothesized population mean. The probability of a Type I error is less than 5%.You are conducting a multinomial hypothesis test (α= 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ObservedFrequency ExpectedFrequency A 17 B 22 C 11 D 13 E 17 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.)χ2= What are the degrees of freedom for this test?d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = Is the p-value less than αα? yes no This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to…In a test of hypothesis, the null hypothesis is that the population mean is equal to 24 and the alternative hypothesis is that the population mean is not equal to 24. The test is to be made at the 5% significance level. The critical values of z are: a. –2.07 and 2.07 b. –1.65 and 1.65 c. –1.96 and 1.96 d. –2.17 and 2.17
