Part V: The proportion of adults living in a small town who are college graduates is estimated to be p = 0.6. To test this hypothesis, a random sample of 15 adults is selected. If the number of college graduates in the sample is anywhere from 6 to 12, we shall not reject the null hypothesis that p=0.6; otherwise, we shall conclude that p + 0.6. a) Assume that 200 adults are selected, and the fail-to-reject region is defined to be 110
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- A medical researcher wants to determine if the average hospital stay of patients that undergo a certain procedure is less than 6 days. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 6, Alternative Hypothesis: μ < 6. If the researcher takes a random sample of patients and calculates a p-value of 0.4381 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance.Question 12 options: 1) We did not find enough evidence to say the true average hospital stay of patients is longer than 6 days. 2) We did not find enough evidence to say the true average hospital stay of patients is shorter than 6 days. 3) The true average hospital stay of patients is significantly shorter than 6 days. 4) The true average hospital stay of patients is longer than or equal to 6 days. 5) We did not find enough evidence to say a significant difference existsThe National Institute of Mental Health published an article stating that in any one-year period, approximately 9.5 percent of American adults suffer from depression or a depressive illness. Suppose that in a survey of 100 people in a certain town, seven of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult American population. a. Is this a test of one mean or proportion? b. State the null and alternative hypotheses. HO: c. Is this a right-tailed, left-tailed, or two-tailed test? d. What symbol represents the random variable for this test? e. In words, define the random variable for this test. f. Calculate the following: i. x = ii. n=. lii. p' = g. Calculate ox = h. State the distribution to use for the hypothesis test. i. Find the p-value. j. At a pre-conceived a = 0.05, what is your: i. Decision: ii.…disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with "1" as the leading digit is about 0.301. Now suppose you are an auditor for a very large corporation. The revenue report involves millions of numbers in a large computer file. Let us say you took a random sample of n = 223 numerical entries from the file and r = 48 of the entries had a first nonzero digit of 1. Let p represent the population proportion of all numbers in the corporate file that have a first nonzero digit of 1.(i) Test the claim that p is less than 0.301. Use ? = 0.05. (a) What is the level of significance?State the null and alternate hypotheses. H0: p < 0.301; H1: p = 0.301H0: p = 0.301; H1: p > 0.301 H0: p = 0.301; H1: p < 0.301H0: p = 0.301; H1: p ≠ 0.301 (b) What sampling distribution will you use? The standard normal, since np > 5 and nq > 5. The standard normal, since np < 5 and nq <…
- Suppose the Drug Company develops a new drug, designed to prevent colds. The company states that the drug is equally effective for men and women. To test this claim, they choose a simple random sample of 100 women and 200 men from a population of 5,000 volunteers. At the end of the study, 38% of the women caught a cold; and 51% of the men caught a cold. Based on these findings, can we reject the company's claim that the drug is equally effective for men and women? Use a 0.05 level of significance.A news article estimated that only 6% of those ages 65 and older who prefer to watch the news, rather than to read or listen, watch the news online. This estimate was based on a survey of a large sample of adult Americans. Consider the population consisting of all adult Americans ages 65 and older who prefer to watch the news, and suppose that for this population the actual proportion who prefer to watch online is 0.06. (a) A random sample of n = 100 people will be selected from this population and p̂, the proportion of people who prefer to watch online, will be calculated. What are the mean and standard deviation of the sampling distribution of p̂? (Round your standard deviation to four decimal places.) meanstandard deviation (b) Is the sampling distribution of p̂ approximately normal for random samples of size n = 100? Explain. (Select all that apply.) the sampling distribution of p̂ is approximately normalthe sampling distribution of p̂ is not approximately normalnp is…You are conducting a study to see if the proportion of voters who prefer the Democratic candidate is significantly different from 72% at a level of significance of a = 0.10. According to your sample, 63 out of 83 potential voters prefer the Democratic candidate. a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: v Select an answer v (please enter a decimal) H1: ? v Select an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population proportion is not significantly different from 72% at a = 0.10, so there is not sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is different from 72%. O The data suggest the…
- A survey is conducted to determine if there is a difference in the proportion of students, parents, and What are the appropriate hypotheses to determine if the distribution of response differs among these three populations? teachers who volunteer at least once a month. To investigate, a random sample of 45 students, 25 parents, and 12 teachers was selected from a large high school. The data are displayed in the table. O Ho: There is a difference in the distribution of responses among these three populations. Hg: There is no difference in the distribution of Student Parent Teacher responses among these three populations. 12 O Ho: There is no difference in the distribution of Yes 24 Volunteer? responses among these three populations. Hg: There is a difference in the distribution of No 21 13 response among these three populations. Họ: There is no association between the type of person who is surveyed and the response. Hạ: There is an association between the type of person who is surveyed…At ABC College it is estimated that at most 10% of the students use public transportation to the college. Does it seem to be a valid estimate if, in a random sample of 120 students, 25 students use public transportation. (Use α = .01)A news article estimated that only 6% of those ages 65 and older who prefer to watch the news, rather than to read or listen, watch the news online. This estimate was based on a survey of a large sample of adult Americans. Consider the population consisting of all adult Americans ages 65 and older who prefer to watch the news, and suppose that for this population the actual proportion who prefer to watch online is 0.06. (a) A random sample of n = 100 people will be selected from this population and p̂, the proportion of people who prefer to watch online, will be calculated. What are the mean and standard deviation of the sampling distribution of p̂? (Round your standard deviation to four decimal places.) meanstandard deviation (b) Is the sampling distribution of p̂ approximately normal for random samples of size n = 100? Explain. (Select all that apply.) the sampling distribution of p̂ is approximately normalthe sampling distribution of p̂ is not approximately normalnp is…
- Answer A, B1, and B2: A. The National Institute of Mental Health published an article stating that in any one-year period, approximately 9.5 percent of American adults suffer from depression or a depressive illness. Suppose that in a survey of 100 people in a certain town, seven of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult American population. B. Researchers interested in lead exposure due to car exhaust sampled the blood of 52 police officers subjected to constant inhalation of automobile exhaust fumes while working traffic enforcement in a primarily urban environment. The blood samples of these officers had an average lead concentration of 124.32 µg/l and a SD of 37.74 µg/l; a previous study of individuals from a nearby suburb, with no history of exposure, found an average blood level…According to the 2000 U.S. Census Bureau, in 2000, 9.5 percent of children in the state of Ohio were not covered by private or government health insurance. In the neighboring state of Pennsylvania, 4.9 percent of children were not covered by health insurance. Assume that these proportions are parameters for the child populations of the respective states. If a random sample of size 100 children is drawn from the Ohio population, and an independent random sample of size 120 is drawn from the Pennsylvania population, what is the probability that the samples would yield a difference, ^p1 - ^p2 of .09 or more?A December 2017 Gallup Poll reported that 43% of Americans use the internet for an hour or more each day. You suspect that a greater proportion of students at your school use the internet that much. You take a random sample of 60 students and find that 36 of them use the internet for an hour or more each day. Assume your school has more than 600 students. You will test the hypotheses H, : p = 0.43, H,:p>0.43 , where p= the true proportion of students at your school who use the internet for an hour or more each day. Which of the following gives the correct test statistic for this test? 0.43 - 0.6 Z = (0.6)(0.4) 60 0.43-0.6 (0.6)(0.4) 600 0.6-0.43 (0.6)(0.4) 60 0.6 - 0.43 (0.43)(0.57) 60 36 - 60 (36)(24) 60