8) The Discovery Automobile Company is attempting to determine if it should retain apreviously popular sports car model called El Nino. A random sample of 500consumers is obtained, and each person in the sample is asked if he/she would stillconsider purchasing an El Nino. To determine if El Nino should be retained, thesample proportion of respondents who said yes, p, is used at a level a = 0.05 to test thehypothesis Ho : P 2 0.5 against H1 : P < 0.5. What value of the sample proportion, p, isrequired to reject the null hypothesis?

Given, Sample size = 500 Hypothesis : H0 : p ≥0.5 H1 : p < 0.5 Left tailed test.…

Answered: 8) The Discovery Automobile Company is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

Two groups were polled about their attitudes towards capital punishment. In one group 30 out of 100 favored capital punishment, and in the other group 40 out of 80 favored capital punishment. Calculate an appropriate test value test the hypothesis that the population proportions are the same.
According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 320 community college students at random and finds that 135 of them have a smart phone. In testing the hypotheses: Ho: p = 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for #3 and #4. 1. This is an example of a hypothesis test. 2. Find the standard error. 3. Find the z value. 4. Find the p-value. 5. The communication professor should the null hypothesis.
A random sample of n1 = 157 people ages 16 to 19 were taken from the island of Oahu, Hawaii, and 12 were found to be high school dropouts. Another random sample of n2 = 129 people ages 16 to 19 were taken from Sweetwater County, Wyoming, and 6 were found to be high school dropouts. Do these data indicate that the population proportion of high school dropouts on Oahu is different (either way) from that of Sweetwater County? Use a 1% level of significance. (a) What is the level of significance? What is the value of the sample test statistic? (Test the difference p1 − p2. Do not use rounded values. Round your final answer to two decimal places.) (c) Find (or estimate) the P-value. (Round your answer to four decimal places.)
For several decades, it was a common practice in Southern California for houses to be built with pools in the backyard (as any airplane flight which ends at a Southern California airport will reveal). Now, however, that practice may be changing, possibly because of the recent demand for landscaped homes, which experts believe help reduce pollution. A recent study examined a random sample of 167 houses built in Southern California between 1950 and 1985 and an independent, random sample of 80 houses built in Southern California from 1992 to the present. The sample of houses built in 1950-1985 contained 71 houses with pools, and the sample of houses built from 1992-present contained 31 houses with pools. Based on this survey, can we conclude, at the 0.05 level of significance, that the proportion p1 of all Southern California houses built in 1950-1985 that were built with pools is greater than the proportion p2 of all Southern California houses built from…
If Miller (2008) wanted to know if males consume significantly more energy drinks than the overall population average, which of the following are the correct hypotheses?
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,476 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 153 of their customers and calculates that these customers used an average of 10,767 kWh of electricity last year. Assuming that the population standard deviation is 2478 kWh, is there sufficient evidence to support the power company's claim at the 0.05 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,069 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 171 of their customers and calculates that these customers used an average of 10,461 kWh of electricity last year. Assuming that the population standard deviation is 2973 kWh, is there sufficient evidence to support the power company's claim at the 0.01 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,941 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 115 of their customers and calculates that these customers used an average of 11,425 kWh of electricity last year. Assuming that the population standard deviation is 3217 kWh, is there sufficient evidence to support the power company's claim at the 0.02 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,069 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 171 of their customers and calculates that these customers used an average of 10,461 kWh of electricity last year. Assuming that the population standard deviation is 2973 kWh, is there sufficient evidence to support the power company's claim at the 0.01 level of significance? Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.
Homechooling has become very popular in the United States, and many colleges try to attract students from this group. Evidence suggests that approximately 90% of all homeschooled children attend college. To check this claim, a random sample of 208 homeschooled children was obtained, and 180 of them were found to have attended college. The researcher wishes to determine whether the proportion of homeschool children who attend college is different from 0.90. Test an appropriate hypothesis and state your conclusion. Make sure to state and check all conditions and state your conclusion in context.
According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 323 community college students at random and finds that 134 of them have a smart phone. In testing the hypotheses: Ho: p= 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for # 3 and #4. 1. I 4. Find the p-value.-- 5. The communication professor should the null hypothesis.
A researchers is interested in the amount of sleep an individual receives after consuming a sleeping aid (Melatonin, Valerian root, and Placebo). The researcher randomly selects individuals into either group. However, some individuals drop out of the study which results in unequal sample sizes. Melatonin: n=6, M=14, T=84, SS=60 Valerian: n=10, M=13, T=130, SS=90 Placebo: n=4, M=9, T=36, SS=37 N=20, G=250, x2=3377 Calculate the F-ratio

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