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The decision is to (p-value = 0.092). There is the with student loan debt is hypothesis evidence that the proportion of

The decision is to (p-value = 0.092). There is the with student loan debt is hypothesis evidence that the proportion of

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Suppose that a 2013 survey revealed that 69.1% of recent college graduates had student loan debt. Amy suspects that this proportion has increased, so she formulated the null hypothesis Ho: p = 0.691 and the alternative hypothesis H₁: p > 0.691, where p is the proportion of 2015 college graduates who have student loan debt. She obtained a simple random sample of 200 college graduates from the class of 2015 and found that 147 of them have student loan debt. Using this information, she calculated the following summary statistics. Sample Sample Sample size count proportion n 200 X 147 The decision is to null equal to (p-value = 0.092). There is alternative p 0.735 0.10 If Amy requires her results to be statistically significant at a level of α = 0.10, use the data presented to fill in the blanks and complete the sentences that form Amy's conclusion. accept Standard insufficient error SE 0.033 not equal to Statistic Z 1.33 with student loan debt is the Answer Bank all 2015 college graduates p-value P 0.092 fail to reject evidence that the proportion of 0.092 the 200 college graduates in the sample less than hypothesis 0.033 sufficient 0.691 greater than reject 0.735
Transcribed Image Text:Suppose that a 2013 survey revealed that 69.1% of recent college graduates had student loan debt. Amy suspects that this proportion has increased, so she formulated the null hypothesis Ho: p = 0.691 and the alternative hypothesis H₁: p > 0.691, where p is the proportion of 2015 college graduates who have student loan debt. She obtained a simple random sample of 200 college graduates from the class of 2015 and found that 147 of them have student loan debt. Using this information, she calculated the following summary statistics. Sample Sample Sample size count proportion n 200 X 147 The decision is to null equal to (p-value = 0.092). There is alternative p 0.735 0.10 If Amy requires her results to be statistically significant at a level of α = 0.10, use the data presented to fill in the blanks and complete the sentences that form Amy's conclusion. accept Standard insufficient error SE 0.033 not equal to Statistic Z 1.33 with student loan debt is the Answer Bank all 2015 college graduates p-value P 0.092 fail to reject evidence that the proportion of 0.092 the 200 college graduates in the sample less than hypothesis 0.033 sufficient 0.691 greater than reject 0.735
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