The decision is to (p-value = 0.092). There is the with student loan debt is hypothesis evidence that the proportion of
The decision is to (p-value = 0.092). There is the with student loan debt is hypothesis evidence that the proportion of
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question

Transcribed Image Text:Suppose that a 2013 survey revealed that 69.1% of recent college graduates had student loan debt. Amy suspects that this
proportion has increased, so she formulated the null hypothesis Ho: p = 0.691 and the alternative hypothesis H₁: p > 0.691,
where p is the proportion of 2015 college graduates who have student loan debt. She obtained a simple random sample of 200
college graduates from the class of 2015 and found that 147 of them have student loan debt. Using this information, she
calculated the following summary statistics.
Sample Sample Sample
size
count
proportion
n
200
X
147
The decision is to
null
equal to
(p-value = 0.092). There is
alternative
p
0.735
0.10
If Amy requires her results to be statistically significant at a level of α = 0.10, use the data presented to fill in the blanks and
complete the sentences that form Amy's conclusion.
accept
Standard
insufficient
error
SE
0.033
not equal to
Statistic
Z
1.33
with student loan debt is
the
Answer Bank
all 2015 college graduates
p-value
P
0.092
fail to reject
evidence that the proportion of
0.092
the 200 college graduates in the sample
less than
hypothesis
0.033
sufficient
0.691
greater than
reject
0.735
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