Part BThe stress-strain diagram for a steel alloy having anoriginal diameter of 1.0 in. and a gage length of7 in. is shown in the figure below. (Eigure 1)Determine the load on the specimen that causes yielding.Express your answer to three significant figures and include appropriate units.HAPy- ValueUnitsSubmitRequest AnswerPart CFiguret oft>Determine the ultimate load the specimen will support.Express your answer to three significant figures and include appropriate units.NO706050P. -ValueUnits403020SubmitBequest Answer10(in/in)o G04 0m 12 016 020 024 02a aa omamsProvide Feedback

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Part B The stress-strain dagram for a steel aloy having an original diameter of 1.0 in. and a gage length of 7 in. is shown in the figure below (Eigure 1) Determine the load on the specimen that causes yielding Express your answer to three significant figures and include appropriate units. Py Value Units Submit Request Answer Part C Figure Determine the ultimate load the specimen will support. Express your answer to three significant figures and include appropriate units. 70 P.- Value Units 30 20 Submit Bequest Answer o G04 0m 12 66 030 4 tin/in) Provide Feedback

Part B The stress-strain dagram for a steel aloy having an original diameter of 1.0 in. and a gage length of 7 in. is shown in the figure below (Eigure 1) Determine the load on the specimen that causes yielding Express your answer to three significant figures and include appropriate units. Py Value Units Submit Request Answer Part C Figure Determine the ultimate load the specimen will support. Express your answer to three significant figures and include appropriate units. 70 P.- Value Units 30 20 Submit Bequest Answer o G04 0m 12 66 030 4 tin/in) Provide Feedback

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...

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A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The wire is made of a copper alloy having a stress-strain relationship that may be described mathematically by =18,0001+30000.03(=ksi) in which is nondimensional and has units of kips per square inch (ksi). (a) Construct a stress-strain diagram for the material. (bj Determine the elongation, of the wire due to the Forces P. (c) IF the forces are removed, what is the permanent set of the bar? (d) If the forces are applied again, what is the proportional limit?
diagram and determine approximately the modulus of elasticity, the yield stress, the ultimate stress, and the fracture 2.00 in. The data is listed in the table. Plot the stress-strain 8-1. A tension test was performed on a steel specimen n original diameter of 0.503 in. and gage length of PROBLEMS *84. origi the f having an for t and stress. Use a scale of 1 in. Dodraw the elastic region, using the same stress scale but a 20 ksi and 1 in. = 0.05 in./in. strain scale of 1 in.= 0.001 in./in. Load (kip) Elongation (in.) 0. 0. 0.0005 0.0015 1.50 4.60 8.00 11.00 0.0025 0.0035 0.0050 11.80 11.80 0.0080 0.0200 12.00 16.60 0.0400 0.1000 0.2800 20.00 21.50 19.50 18.50 0.4000 0.4600 Prob. 8-1
Example: Convert the change in length data in Table 3-2 to engineering stress and strain and plot a stress-strain curve Homework- help Table 3-2 The results of a tensile test of a 0.505 in. diameter aluminum alloy test bar, initial length (1o) = 2 in. Calculated LTO Load (Ib) Change in Length (in.) Stress (psi) Strain (in./in.) 0.000 1000 0.001 0.0005 4,993 14,978 24,963 34,948 37,445 39,442 39,941 39,691 37,944 3000 0.003 0.0015 5000 0.005 0.0025 7000 0.007 0.0035 7500 0.030 0.0150 7900 0.080 0.0400 8000 (maximum load) 0.120 0.0600 7950 0.160 0.0800 7600 (fracture) 0.205 0.1025
Solve this early both parts
The proof stress of a material under tensile loading can be considered as can be considered as equivalent to the ultimate tensile strength for aluminium alloys being only applied to engineering steels during a tensile test the intercept on the stress stain curve for a given strain where a line draw is parallel to the elastic response line. the stress at yield for materials have no defined yield stress
Stress Strain Diagram The Data shown in the table have been obtained from a tensile test conducted on a high-strength steel. The test specimen had a diameter of 0.505 inch and a gage length of 2.00 inch. Using software. plot the Stress-Strain Diagram for this steel and determine its: A= TTdT(050s A %3D 1. Proportional Limit, 2. Modulus of Elasticity, 3. Yield Strength (SY) at 0.2% Offset, 4. Ultimate Strength (Su), 5. Percent Elongation in 2.00 inch, 6. Percent Reduction in Area, 7. Present the results (for Steps 1-6) in a highly organized table. e Altac ie sheet (as problelle 4 A = 0.2.002 BEOINNING of the effort Elongation (in) Elongation (In) Load Load #: #3 (Ib) (Ib) 1 0.0170 15 12,300 0.0004 1,500 16 12,200 0.0200 0.0010 3. 3,100 17 12,000 0.0275 0.0016 4,700 18 13,000 0.0335 5. 6,300 0.0022 19 15,000 0.0400 0.0026 6. 8,000 20 16,200 0.055 0.0032 9,500 21 17,500 0.0680 0.0035 8. 11,000 22 18,800 0.1080 0.0041 11,800 23 19,600 0.1515 0.0051 24 20,100 0.2010 10 12,300 0.0071 25…
Part A The stress-strain diagram for a steel alloy having an original diameter of 0.40 in. and a gage length of 9 in. is shown in the figure below. (Figure 1) Determine the modulus of elasticity for the material. Express your answer to three significant figures and include appropriate units. HA ? Eapprox = Value Units Submit Request Answer Figure < 1 of 1 Part B a (ksi) 80 Determine the load on the specimen that causes yielding. 70 Express your answer to three significant figures and include appropriate units. 60 50 40 HA 30 20 Py = Value Units 10 € (in./in.) 0.04 0,08 0.12 0,16 0,20 0,24 0,28 O 0.0005 0.001 0.0015 0.002 0.0025 0.0030.0035 Request Answer Submit
A ul ? KBIS M 1:11 O photo_2021-0... -> 200 stress 150 (MPa) (00 50 0-2 strain From the tensile stress-strain behavior for the brass specimen d the diamcter is 12-8 mm Calculate the folluding:- 1- The Yield stress. 2- Modulus of elasticity. 3 - The Tensile strength . II
A tensile specimen havign a diameter of 6 mm and a gauge length of 50 mm was tested to fracture and the stress-strain diagram is show. Poisson's ratio of material, v = 0.3 Determine the load P that the sample is subjected to when a stress of 300 MPa is applied. What is the instantaneous diameter of the sample given a longitudinal strain of 0.002?
A tensile test specimen of 1045 hot-rolled steel having a diameter of 0.505 in. and a gage length of 2.00 in. was tested to fracture. Stress and strain data obtained during the test are shown. Determine the ultimate strength. Stress (ksi) 60 50- 40- 30- 20 10- 0 0 0 Upper scale O 66 ksi 28 ksi O 72 ksi O 53 ksi O 62 ksi Lower scale. 0.025 0.050 0.075 0.100 0.125 0.150 0.175 0.002 0.004 0.006 0.008 0.010 0.012 0.014 Strain (in./in.)
296 8-10 A 0.505-in.-diameter metal bar with a 2-in. gage length o is subjected to a tensile test. The following measurements are made in the plastic region: 8-13 Chapter 8 Strain Hardening and Annealing Figure 8-23 shows a plot of the natural log- arithm of the true stress versus the natural logarithm of the true strain for a Cu-30% Zn sample tested in tension. Only the plastic portion of the stress strain curve is shown. Determine the strength coefficient K and the work-hardening exponent n. Change in Force Gage length Diameter (lb) (in.) (Al) (in.) 21 27,500 0.2103 0.4800 27,000 0.4428 0.4566 20 25,700 0.6997 0.4343 8-11 Determine the strain-hardening exponent for the metal. Is the metal most likely to be FCC, BCC, or HCP? Explain. A 1.33-cm-diameter metal bar with a 3-cm gage length (10) is subjected to a ten- sile test. The following measurements are made in the plastic region: In [True stress (Pa)] 18 16 -2.5 -2.0 -1.5 -1.0 -0.5 -0.0 In (True strain) Figure 8-23 The natural…
Only answer the graph portion, the image of the bolt is invade the area or length is relevant