• Part A Two positive point charges are 5.00 cm apart. If the electric potential energy is 75.0 µJ, what is the magnitude of the force between the two charges? Express your answer with the appropriate units. HÁ X•10" Value Units
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- Figure 3.0 cm •A E = 1000 V/m 7.0 cm 1 of 1 B. What is the potential difference between A and B? Express your answer in volts. VA - VB = Submit ΠΫΠΙ ΑΣΦ Previous Answers Request Answer X Incorrect; Try Again ? V• C E • A • B An electric field of strength E = 5000 N/C is directed along the +x-axis as shown. A electron is initially at rest at point B. Electron Charge = -1.6x10-19 C Electron Mass = 9.11 ×10-31 Kg What is the magnitude of the potential difference between point B and point A if the distance between these two points is 25 cm? O V O125 V O 250 V O1,250 V Submit Answer Tries 0/2 How much kinetic energy (in Joules) will the electron gain by moving to the higher potential at point A? 02.0 x 10-16 j O-2.0 x 10-16 J 02.4 x10-17 J O-2.4 x10-17 j Submit Answer Tries 0/2 What is the speed of the electron at point A? 01.7 x 105 m/s 04.9 x 105 m/s O2.1 x107 m/s 5.8 x107 m/sFigure 9 3.0 cm 14.0 cm + 3.0 nC < 3.0 nC + 1 of 1 Part A What is the electric potential energy of the group of charges in (Figure 1)? Assume that q = -7.0 nC. Express your answer with the appropriate units. U = Submit μÅ Value Provide Feedback Request Answer Units ?
- Please solveThe three q1-q2-q3= 55 µC charges came into the arrangement shown below from very far apart. q1 is located at (0.00, 5.16) cm, q2 is located at (0.00, -5.16) cm and q3 located at (10.56, 0.00) cm a) How much work must be done to move the three charges into the arrangement shown if they started very far apart? b) What is the work if the particle on the right, q3, with mass 54.7 g, is released from rest and allowed to move freely to point P twice 10.56 distance, figure below? c) How fast, in m/s, is q3 moving when it has moved to point P, twice 10.56 distance? y (cm) 91 92 93 To continue, please submit the result of part (c) in units of m/s. Add your answer x (cm) wwwA uniform electric field is produced which can be represented by E = (20, 000 à - 50, 000 ) V/m. Part A What is the potential difference between = -5 cm and y, = 5 cm in this uniform electric field? • View Available Hint(s) AV = 5000 y Submit Previous Answers Correct Part B What is the potential difference between (0 cm, 2 cm ) and ( 6 em, -3 cm )? ? AV = 3700 V Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining
- What is the capacitance? Two parallel 5.0-cm-diameter flat aluminum electrodes are spaced 0.50 mm apart. The electrodes are connected to a 100 V battery. Express your answer with the appropriate units. • View Available Hint(s) HA ? C = 34.75 nF Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining Part B What is the magnitude of the charge on each electrode? Express your answer with the appropriate units. • View Available Hint(s) HA ? Q = 3.475 nc Submit Previous Answers PearsonQuestion 15 Two stationary positive point charges, charge 1 of magnitude 3.15 nC and charge 2 of magnitude 1.65 nC , are separated by a distance of 31.0 cm . An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. Part A What is the speed vfinal of the electron when it is 10.0 cm from charge 1? Express your answer in meters per second. • View Available Hint(s) ΑΣφ Vfinal m/s Submit#2 Electric Potential Energy Two 1.00 × 10–6 C charges with masses each of 0.005 kg are separated by 0.02 m. What is the electrostatic potential energy of the configuration? Recall that: 1 Q.Q2 U = 4T€0 R where R is the separation among the two charges. А. 0.125 J B. 0.224 J C. 0.349 J D. 0.450 J 0000
- View V Plate Charges V Electric Field Lines 10 13 1013 Meters V Capacitance V Plate Charge V Stored Energy Disconnect Battery V Voltmeter O Electric Field Detector Reset All Capacitance Plate Charge (top) Stored Energy Separation 0.71x10-12 F 2.61x1013 c 0.48x10-13 J 5.0 mm 0.369 V 1.5 V Plate Area 400.0 mm L-1.5 VPart A Two stationary positive point charges, charge 1 of magnitude 3.10 nC and charge 2 of magnitude 1.60 nC, are separated by a distance of 46.0 cm An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed vfinal of the electron when it is 10.0 cm from charge 1? Express your answer in meters per second. > View Available Hint(s) 1 AZ中 να ΑΣφ Ufinal m/s S. Submit « Previous hp |3DI Review | Constants The ammonia molecule (NH3) has a dipole moment of 5.0 x 10-30 C.m. Ammonia molecules in the gas phase are placed in a uniform electric field E with magnitude 1.4x106 N/C. Part A What is the change in electric potential energy when the dipole moment of a molecule changes its orientation with respect to E from parallel to perpendicular? Express your answer using two significant figures. ΑΣφ ? AU = J