An electric field of strength E = 1600 N/C is directed along the +x-axis as shown. An electron is initially at rest at point B. Electron Charge = -1.6x10-19 C %3D What is the work done by the electric field on the electron after it has moved a distance of 10 cm from point B to point A?
An electric field of strength E = 1600 N/C is directed along the +x-axis as shown. An electron is initially at rest at point B. Electron Charge = -1.6x10-19 C %3D What is the work done by the electric field on the electron after it has moved a distance of 10 cm from point B to point A?
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![• C
E
• A
• B
An electric field of strength E = 1600 N/C is directed along the +x-axis as shown.
An electron is initially at rest at point B.
%3D
Electron Charge = -1.6x10 19 C
%3D
What is the work done by the electric field on the electron after it has moved a distance of 10 cm from point B to
point A?
O160 J
02.6 x10-17 J
-2.6 x10-17 J
-160 J
Submit Answer
Tries 0/2
What is the work done by the electric field on the electron after it has moved a distance of 10 cm from point A to
point B?
O160 J
2.6 x10-17 J
-2.6 x10-17 J
O-160 J](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F60233bc8-b7a4-4cb1-97f6-a0fef93353db%2F6b762d56-b669-4492-8bd1-2c8150886655%2Fhra219c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:• C
E
• A
• B
An electric field of strength E = 1600 N/C is directed along the +x-axis as shown.
An electron is initially at rest at point B.
%3D
Electron Charge = -1.6x10 19 C
%3D
What is the work done by the electric field on the electron after it has moved a distance of 10 cm from point B to
point A?
O160 J
02.6 x10-17 J
-2.6 x10-17 J
-160 J
Submit Answer
Tries 0/2
What is the work done by the electric field on the electron after it has moved a distance of 10 cm from point A to
point B?
O160 J
2.6 x10-17 J
-2.6 x10-17 J
O-160 J
Expert Solution
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Step 1
The electric field is directed from A to B ,
Hence, the electron will feel a force from B to A ,
Force F = e x |E | , where e = 1.6 x 10-19 C and E = 1600 N /C
F = 2560 10-19 N
Work done by the electric field to move this charge by 10 cm = 0.1 m ,
W = F x displacement
W = 2560 x 10-19 x 0.1
W = 256 x 10-19
WBA = 2.56 10-17 J
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