• Part A Learning Goat To understand the magnetic force on a straight current-carying wire in a unform magnetic feld Magnetic telds esert forces on moving charged particles, whether those charges are moving independently or are confined to a current-carrying wire The magnetic force F on an individual moving charged particie depends on ts velocity e and charge q in the case of a current-carrying wire many charged particies are simultaneously in motion, so the magnetic force depends on the total current / and the length of the wire L Consider a wire of length L = 0.30 m that runs north-south on a horizontal surface There is a current of I=0 50 A fowing north in the wre (The rest of the crcut which actualtly delivers this current, is not shown.) The Earth's magnetic field at this location has a magnitude of 0.50 gass (or in Si units. 0.5 x 10 tesla and points north and 30 degrees down trom the horizontal, toward the ground What is the size of the magnetic force on the wire due to the Earth's magnetic fei in considering the agreement of unta, necall that 1T=1IN/(A- m) (Egure 1) Express your answer in newtons to two significant figures. View Available Hintis) The size of the magnetic force on a straight wire of length L carrying current Ina unform magnetic teid with strength Bis F-ILB sin(6) O AE + Here eis the angie between the direction of the current (along the wire) and the direction of the magnetic feld Hence Bsin(6) refers to the component of the magnetic feld that is perpendicular to the wire, B Thus this ation can aiso be unitten as F= ILB The direction of the magnetic force on the wire can be described using a nght-hand rule" This wil be discussed after Part E N Submit • Part B Now assume that a strong, uniform magnetic field of size 0 55 T pointing straight down is applied What is the sze of the magnetic force on the we due to ths appled magnetic field? Ignore the effect of the Earth's magnetic field Figure 1 of 2 > Express your answer in newtons to two significant figures. • View Available Hintis) Up N +E Submit S Down The direction of the magnetic force is perpendicular to both the direction of the current flow and the direction of the magnetic teld Here is a right-nand nule to heip you delermine the direction of the magnetic force (Eaure 2) P Pearson

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• Part A
Learning Goal:
To understand the magnetic force on a straight current-carrying wire in a
uniform magnetic field.
Magnetic fields exert forces on moving charged particles, whether those
charges are moving independently or are confined to a current-carrying
wire The magnetic force F on an individual moving charged particle
depends on its velocity e and charge q. In the case of a current-carrying
wire many charged particles are simultaneously in motion, so the magnetic
force depends on the total current I and the length of the wire L.
Consider a wire of length L = 0.30 m that runs north-south on a horizontal surface. There is a curent of I= 0 50 A fiowing north in the wire (The rest of the circuit, which actualy
delivers this current, is not shown.) The Earth's magnetic field at this location has a magnitude of 0.50 gauss (or. in Si units, 0.5 x 10 tesla) and points north and 38 degrees
down trom the horizontal, toward the ground. What is the size of the magnetic force on the wire due to the Earth's magnetic field? in considering the agreement of units, recall that
1T=1N/(A- m) (Figure 1)
Express your answer in newtons to two significant figures.
>View Available Hint(s)
The size of the magnetic force on a straight wire of length L carrying current
Ina uniform magnetic field with strength Bis
F= ILB sin(0)
Here e is the angie between the direction of the current (along the wire) and
the direction of the magnetic field. Hence Bsin(6) refers to the component
of the magnetic field that is perpendicular to the wire, B Thus this
equation can also be written as F = ILB
The direction of the magnetic force on the wire can be described using a
"nght-hand ruie" This will be discussed after Part B.
N
Submit
• Part B
Now assume that a strong, uniform magnetic field of size 0.55 T pointing straight down is applied. What is the size of the magnetic force on the wire due to this applied magnetic
field? Ignore the effect of the Earth's magnetic field.
Figure
1 of 2 >
Express your answer in newtons to two significant figures.
> View Available Hint(s)
V AE
Up
N
E
Submit
Down
The direction of the magnetic force is perpendicular to both the direction of the current flow and the direction of the magnetic field Here is a "right-nand rule" to help you delermine the
direction of the magnetic force. (Elgure 2)
Pearson
Transcribed Image Text:• Part A Learning Goal: To understand the magnetic force on a straight current-carrying wire in a uniform magnetic field. Magnetic fields exert forces on moving charged particles, whether those charges are moving independently or are confined to a current-carrying wire The magnetic force F on an individual moving charged particle depends on its velocity e and charge q. In the case of a current-carrying wire many charged particles are simultaneously in motion, so the magnetic force depends on the total current I and the length of the wire L. Consider a wire of length L = 0.30 m that runs north-south on a horizontal surface. There is a curent of I= 0 50 A fiowing north in the wire (The rest of the circuit, which actualy delivers this current, is not shown.) The Earth's magnetic field at this location has a magnitude of 0.50 gauss (or. in Si units, 0.5 x 10 tesla) and points north and 38 degrees down trom the horizontal, toward the ground. What is the size of the magnetic force on the wire due to the Earth's magnetic field? in considering the agreement of units, recall that 1T=1N/(A- m) (Figure 1) Express your answer in newtons to two significant figures. >View Available Hint(s) The size of the magnetic force on a straight wire of length L carrying current Ina uniform magnetic field with strength Bis F= ILB sin(0) Here e is the angie between the direction of the current (along the wire) and the direction of the magnetic field. Hence Bsin(6) refers to the component of the magnetic field that is perpendicular to the wire, B Thus this equation can also be written as F = ILB The direction of the magnetic force on the wire can be described using a "nght-hand ruie" This will be discussed after Part B. N Submit • Part B Now assume that a strong, uniform magnetic field of size 0.55 T pointing straight down is applied. What is the size of the magnetic force on the wire due to this applied magnetic field? Ignore the effect of the Earth's magnetic field. Figure 1 of 2 > Express your answer in newtons to two significant figures. > View Available Hint(s) V AE Up N E Submit Down The direction of the magnetic force is perpendicular to both the direction of the current flow and the direction of the magnetic field Here is a "right-nand rule" to help you delermine the direction of the magnetic force. (Elgure 2) Pearson
Review I Constants
The direction of the magnetic force is perpendicular to both the direction of the current flow and the direction of the magnetic field Here is a "right-hand rule to help you determine the
direction of the magnetic force (Eigure 2)
Learning Goal:
To understand the magnetic force on a straight current-carrying wire in a
uniform magnetic field
1. Straighten the fingers of your nght hand and point them in the direction of the current.
2. Rotate your arm until you can bend your fingers to point in the direction of the magnetic field.
3. Your thumb now points in the direction of the magnetic force acting on the wire.
Magnetic fields exert forces on moving charged particles, whether those
charges are moving independently or are confined to a current-carrying
• Part C
wire. The magnetic force Fon an individual moving charged particle
depends on its velocity v and charge q in the case of a current-carrying
wire, many charged particies are simultaneously in motion, so the magnetic
force depends on the total current I and the length of the wire L
What is the direction of the magnetic force acting on the wire in Part B due to the applied magnetic field?
The size of the magnetic force on a straight wire of length L carrying current
I in a uniform magnetic field with strength Bis
O due north
F= ILB sin(@).
O due south
Here e is the angle between the direction of the current (along the wire) and
the direction of the magnetic field. Hence B sin(8) refers to the component
of the magnetic field that is perpendicular to the wire, B. Thus this
equation can also be written as F = ILB
The direction of the magnetic force on the wire can be described using a
"right-hand rule" This will be discussed after Part B.
O due east
O due west
O straight up
O straight down
Submit
Reguest Answer
Figure
(< 2 of 2 >
Part D
Now let us assume that we are able to reorientate the wire in (Figure 1) and therefore the direction of current flow.
Which of the following situations would result in a magnetic force on the wire that points due north?
Check all that apply.
O Current in the wire flows straight down; the magnetic field points due west
O Current in the wire flows straight up, the magnetic field points due east.
O Current in the wire flows due east the magnetic field points straight down.
O Current in the wire flows due west and slightly up the magnetic field points due east.
O Current in the wire flows due west and slightly down; the magnetic field points straight down.
Pearson
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Transcribed Image Text:Review I Constants The direction of the magnetic force is perpendicular to both the direction of the current flow and the direction of the magnetic field Here is a "right-hand rule to help you determine the direction of the magnetic force (Eigure 2) Learning Goal: To understand the magnetic force on a straight current-carrying wire in a uniform magnetic field 1. Straighten the fingers of your nght hand and point them in the direction of the current. 2. Rotate your arm until you can bend your fingers to point in the direction of the magnetic field. 3. Your thumb now points in the direction of the magnetic force acting on the wire. Magnetic fields exert forces on moving charged particles, whether those charges are moving independently or are confined to a current-carrying • Part C wire. The magnetic force Fon an individual moving charged particle depends on its velocity v and charge q in the case of a current-carrying wire, many charged particies are simultaneously in motion, so the magnetic force depends on the total current I and the length of the wire L What is the direction of the magnetic force acting on the wire in Part B due to the applied magnetic field? The size of the magnetic force on a straight wire of length L carrying current I in a uniform magnetic field with strength Bis O due north F= ILB sin(@). O due south Here e is the angle between the direction of the current (along the wire) and the direction of the magnetic field. Hence B sin(8) refers to the component of the magnetic field that is perpendicular to the wire, B. Thus this equation can also be written as F = ILB The direction of the magnetic force on the wire can be described using a "right-hand rule" This will be discussed after Part B. O due east O due west O straight up O straight down Submit Reguest Answer Figure (< 2 of 2 > Part D Now let us assume that we are able to reorientate the wire in (Figure 1) and therefore the direction of current flow. Which of the following situations would result in a magnetic force on the wire that points due north? Check all that apply. O Current in the wire flows straight down; the magnetic field points due west O Current in the wire flows straight up, the magnetic field points due east. O Current in the wire flows due east the magnetic field points straight down. O Current in the wire flows due west and slightly up the magnetic field points due east. O Current in the wire flows due west and slightly down; the magnetic field points straight down. Pearson Contact Us
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