Long WireA long wire lying along the x-axis carries a current of 2.00 A inthe +x direction. There is a uniform magnetic field present,given by B=0.003i+ 0.004j+0.002k, where i, j, k are theunit vectors along the cartesian coordinate axes') in units ofTesla. Calculate the y-component of the magnetic force actingon a segment of wire of length L = 12.5 cm.-5.00E-3 NUse the formula for the magnetic force on a straight wirecarrying current in a uniform magnetic field. You can find thecross product by applying the right hand rule separately foreach B component.Submit Answer Incorrect. Tries 2/5 Previous Tries

Answered: Image /qna-images/answer/db257efe-b57f-4f9d-b79d-7ab6de40817c.jpg

Answered: A long wire lying along the x-axis…

Similar questions

A charge of 1.2 C having an initial velocity of = 3.91+3.3 m/s enters a region with an electric field È = 3.1î N/C and a magnetic field B = 3.71+4.2k T. Calculate the magnitude of the force on the charge immediately after it enters the region. Express your answer in Newtons (write just the value, not the unit), rounding to one digit after the decimal separator. Add your answer Continue
Problem 2: = A particle with charge +2.0 C moves through a uniform magnetic field. At one instant the velocity vector is v (2î+4ĵ + 6k) m/sec and the magnetic force on the particle is F = (41-20ĵ+ 12k) N. The x and y components of the magnetic field are equal (Bx = By). Thus, the magnetic field is given by B = B×î + B×ĵ + B₂k. What are B× and B₂? Answer: Bx = -3 T and B₂ = −4 T.
A wire 2.55 m long carries a current of 17.3 A and makes an angle of 47.7° with a uniform magnetic field of magnitude B = 1.35 T. Calculate the magnetic force on the wire.
A charge g = +1.60E-12 C moves with speed 4.324 m/s through a constant magnetic field of strength 5.65 T. The charge's velocity vector makes an angle of 25.1° with the direction of the magnetic field. What is the magnetic force exerted on the charge (in Newtons (N))?
A charged particle moves with a speed of 6.0×103 m/s perpendicularly into an uniform magnetic field of magnitude 0.20 T. The charge of the particle is 5.8 ×10-16 C, mass of the particle is 1.2 ×10-21kg. (a) What is the magnitude of the magnetic force on the particle? (b) What could be the radius of the path of the particle if it moves inside the B-field?(c) To avoid the particle being deflected by the magnetic field, (so particle can move straight through the B-field,) an electric field is applied at the same location. What is the magnitude of the E-field? HTML EditorKeyboard Shortcuts