A particle with a charge of 5.00 nC is moving in a uniform magnetic field of B=-(1.27 T)k^. The magnetic force on the particle is measured to be F=-( 4.00×10-7N)^+(7.60×10¯7 N )j^. A. Calculate the x component of the velocity of the particle. -
A particle with a charge of 5.00 nC is moving in a uniform magnetic field of B=-(1.27 T)k^. The magnetic force on the particle is measured to be F=-( 4.00×10-7N)^+(7.60×10¯7 N )j^. A. Calculate the x component of the velocity of the particle. -
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![A particle with a charge of - 5.00 nC is moving in a uniform
magnetic field of B=-(1.27 T)k^. The magnetic force on the
particle is measured to be F=-( 4.00×10- N )^+(7.60×10-7 N )j^.
A. Calculate the x component of the velocity of the particle.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8afdd76b-9f8e-4d06-9032-45f89de6b192%2F146732b6-f887-4d8a-afa8-e52b23cd9d3b%2Fp3f3ect_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A particle with a charge of - 5.00 nC is moving in a uniform
magnetic field of B=-(1.27 T)k^. The magnetic force on the
particle is measured to be F=-( 4.00×10- N )^+(7.60×10-7 N )j^.
A. Calculate the x component of the velocity of the particle.
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