---### Magnetic Forces on a Moving ChargeA charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is \(1.76 \times 10^{-3}\) N. If this same charge were to move at the same speed and the angle between its velocity and the same magnetic field were \(45.6^\circ\), what would be the magnitude of the magnetic force that the charge would experience?#### ExplanationWhen a charged particle moves through a magnetic field, the force (\(F\)) it experiences is given by the equation:\[ F = qvB \sin \theta \]- \( q \) is the charge.- \( v \) is the velocity of the charge.- \( B \) is the magnetic field strength.- \( \theta \) is the angle between the velocity and the direction of the magnetic field.Given:- Initial Force (\( F_1 \)) = \( 1.76 \times 10^{-3} \) N- Initial Angle (\( \theta_1 \)) = \( 90^\circ \)- Angle between velocity and magnetic field in the second scenario (\( \theta_2 \)) = \( 45.6^\circ \)For \(\theta_1 = 90^\circ\),\[ \sin 90^\circ = 1 \]Thus, the force in the first scenario can be written as:\[ F_1 = qvB \]Now for the second scenario where \(\theta_2 = 45.6^\circ\),\[ \sin 45.6^\circ = \sin(0.796 \, \text{radians}) \approx 0.714 \]The magnitude of the new force (\( F_2 \)) is:\[ F_2 = qvB \sin 45.6^\circ = F_1 \cdot \sin 45.6^\circ \]Insert the values:\[ F_2 = (1.76 \times 10^{-3} \, \text{N}) \cdot 0.714 \]\[ F_2 \approx 1.25664 \times 10^{-3} \, \text{N} \]#### Graphs and DiagramsIn the accompanying diagrams:1. **First Diagram**: - Shows the charge \( q \) moving with velocity \( \vec{

Given that A charge is moving to perpendicular to magnetic field Magnatic force(f)=1.76×10^-3N…

Current Attempt in Progress A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 1.76 x 10-3 N. If this same charge were to move at the same speed and the angle between its velocity and the same magnetic field were 45.6°, what would be the magnitude of the magnetic force that the charge would experience? 90 1+1 90° B B B Number i Hint Units

Current Attempt in Progress A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 1.76 x 10-3 N. If this same charge were to move at the same speed and the angle between its velocity and the same magnetic field were 45.6°, what would be the magnitude of the magnetic force that the charge would experience? 90 1+1 90° B B B Number i Hint Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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