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Part A Kepler's Third "Law" states that the square of the orbital period of a planet (T) is proportional to the cube of the planet's average orbital radius (r), T- kr, where k is the proportionality constant connecting T and We can derive Kepler's Third "Law" and show that k = 4r/Gm,un, where G is the universal gravitational constant and mn is the mass of the sun, by O preventing a global thermonuclear war before it ruins our day and then binge watching the first ten seasons of the Walking Dead on Netflix. O setting the acceleration due to gravity at the surface of the planet equal to the acceleration due to gravity at the surface of the sun. O setting the mutual gravitational force between the planet and the sun, Gmplanetmur, equal to the centripetal force acting on the planet. O stealing Robert Hooke's undeveloped idea that the mutual attractive force between the planet and the sun is proportional to 1/. O convincing ourselves that planets in circular orbits are actually in free fall around the sun and then setting the centripetal acceleration of the planet equal to the acceleration due to gravity at the surface of the sun. O combining Kepler's First and Second "Laws" with the well-known relationship distance = rate x time. Submit Request Answer Part B Another step needed to derive Keplers Third "Law" from Newton's Law of Universal Gravitation is O combining Kepler's First and Second "Laws" with Newton's Law of Universal Gravitation, F,= Gm,unmplaner setting the circumference of the planet's orbit equal to 4/G times the radius of the planet's orbit. O convincing ourselves that planets in circular orbits are actually in free fall nd the sun and then setting the centripetal acceleration of the planet equal to the acceleration due to gravity at the surftace of the sun. O applying d = vt, noting that for a complete orbit, d is the circumference of a circle and t is the orbital period T of the planet. O calculating the mass of the planet by examining the orbits of the planet's moons. O smoking the Thanksgiving turkey on the Traeger grill. Submit Request Answer

Part A Kepler's Third "Law" states that the square of the orbital period of a planet (T) is proportional to the cube of the planet's average orbital radius (r), T- kr, where k is the proportionality constant connecting T and We can derive Kepler's Third "Law" and show that k = 4r/Gm,un, where G is the universal gravitational constant and mn is the mass of the sun, by O preventing a global thermonuclear war before it ruins our day and then binge watching the first ten seasons of the Walking Dead on Netflix. O setting the acceleration due to gravity at the surface of the planet equal to the acceleration due to gravity at the surface of the sun. O setting the mutual gravitational force between the planet and the sun, Gmplanetmur, equal to the centripetal force acting on the planet. O stealing Robert Hooke's undeveloped idea that the mutual attractive force between the planet and the sun is proportional to 1/. O convincing ourselves that planets in circular orbits are actually in free fall around the sun and then setting the centripetal acceleration of the planet equal to the acceleration due to gravity at the surface of the sun. O combining Kepler's First and Second "Laws" with the well-known relationship distance = rate x time. Submit Request Answer Part B Another step needed to derive Keplers Third "Law" from Newton's Law of Universal Gravitation is O combining Kepler's First and Second "Laws" with Newton's Law of Universal Gravitation, F,= Gm,unmplaner setting the circumference of the planet's orbit equal to 4/G times the radius of the planet's orbit. O convincing ourselves that planets in circular orbits are actually in free fall nd the sun and then setting the centripetal acceleration of the planet equal to the acceleration due to gravity at the surftace of the sun. O applying d = vt, noting that for a complete orbit, d is the circumference of a circle and t is the orbital period T of the planet. O calculating the mass of the planet by examining the orbits of the planet's moons. O smoking the Thanksgiving turkey on the Traeger grill. Submit Request Answer

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Part A Kepler's Third "Law" states that the square of the orbital period of a planet (T) is proportional to the cube of the planet's average orbital radius (r), T² = kr³, where k is the proportionality constant connecting T2 and We can derive Kepler's Third "Law" and show that k = 4/Gmgun, where G is the universal gravitational constant and msun is the mass of the sun, by %3D preventing a global thermonuclear war before it ruins our day and then binge watching the first ten seasons of the Walking Dead on Netflix. setting the acceleration due to gravity at the surface of the planet equal to the acceleration due to gravity at the surface of the sun. O setting the mutual gravitational force between the planet and the sun, Gmplanetmsunr, equal to the centripetal force acting on the planet. <> O stealing Robert Hooke's undeveloped idea that the mutual attractive force between the planet and the sun is proportional to 1/2. convincing ourselves that planets in circular orbits are actually in free fall around the sun and then setting the centripetal acceleration of the planet equal to the acceleration due to gravity at the surface of the sun. combining Kepler's First and Second "Laws" with the well-known relationship distance = rate x time. Submit Request Answer Part B Another step needed to derive Keplers Third "Law" from Newton's Law of Universal Gravitation is O combining Kepler's First and Second "Laws" with Newton's Law of Universal Gravitation, F, = Gmgunmplanetr. %3D setting the circumference of the planet's orbit equal to 4r/G times the radius of the planet's orbit. convincing ourselves that planets in circular orbits are actually in free fall around the sun and then setting the centripetal acceleration of the planet equal to the acceleration due to gravity at the surface of the sun. applying d = vt, noting that for a complete orbit, d is the circumference of a circle and t is the orbital period T of the planet. O calculating the mass of the planet by examining the orbits of the planet's moons. smoking the Thanksgiving turkey on the Traeger grill. Submit Request Answer
Transcribed Image Text:Part A Kepler's Third "Law" states that the square of the orbital period of a planet (T) is proportional to the cube of the planet's average orbital radius (r), T² = kr³, where k is the proportionality constant connecting T2 and We can derive Kepler's Third "Law" and show that k = 4/Gmgun, where G is the universal gravitational constant and msun is the mass of the sun, by %3D preventing a global thermonuclear war before it ruins our day and then binge watching the first ten seasons of the Walking Dead on Netflix. setting the acceleration due to gravity at the surface of the planet equal to the acceleration due to gravity at the surface of the sun. O setting the mutual gravitational force between the planet and the sun, Gmplanetmsunr, equal to the centripetal force acting on the planet. <> O stealing Robert Hooke's undeveloped idea that the mutual attractive force between the planet and the sun is proportional to 1/2. convincing ourselves that planets in circular orbits are actually in free fall around the sun and then setting the centripetal acceleration of the planet equal to the acceleration due to gravity at the surface of the sun. combining Kepler's First and Second "Laws" with the well-known relationship distance = rate x time. Submit Request Answer Part B Another step needed to derive Keplers Third "Law" from Newton's Law of Universal Gravitation is O combining Kepler's First and Second "Laws" with Newton's Law of Universal Gravitation, F, = Gmgunmplanetr. %3D setting the circumference of the planet's orbit equal to 4r/G times the radius of the planet's orbit. convincing ourselves that planets in circular orbits are actually in free fall around the sun and then setting the centripetal acceleration of the planet equal to the acceleration due to gravity at the surface of the sun. applying d = vt, noting that for a complete orbit, d is the circumference of a circle and t is the orbital period T of the planet. O calculating the mass of the planet by examining the orbits of the planet's moons. smoking the Thanksgiving turkey on the Traeger grill. Submit Request Answer
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