Part A How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation. P4(s) + 10 Cl2(g) → 4 PCI5(g) 1.655 mol 662 mol .331 mol 1.324 mol .993 mol Submit Request Answer Provide Feedback Type here to search
Part A How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation. P4(s) + 10 Cl2(g) → 4 PCI5(g) 1.655 mol 662 mol .331 mol 1.324 mol .993 mol Submit Request Answer Provide Feedback Type here to search
Chapter8: Reaction Rates And Equilibrium
Section: Chapter Questions
Problem 8.32E
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Question
How many moles of PCl5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation?
P4(s)+10Cl2(g) > 4PCI5(g)
![Part A
How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation.
P4(s) + 10 Cl2(g) → 4 PCI5(g)
1.655 mol
662 mol
.331 mol
1.324 mol
.993 mol
Submit
Request Answer
Provide Feedback
Type here to search](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe93426cb-0db1-44ce-8246-5d36dba02057%2Fa1a54a64-b54b-455c-a8aa-4d6c9b7cf0b2%2Fs1ede15.jpeg&w=3840&q=75)
Transcribed Image Text:Part A
How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation.
P4(s) + 10 Cl2(g) → 4 PCI5(g)
1.655 mol
662 mol
.331 mol
1.324 mol
.993 mol
Submit
Request Answer
Provide Feedback
Type here to search
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