Part A How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation. P4(s) + 10 Cl2(g) → 4 PCI5(g) 1.655 mol 662 mol .331 mol 1.324 mol .993 mol Submit Request Answer Provide Feedback Type here to search

Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
Publisher:Seager
Chapter8: Reaction Rates And Equilibrium
Section: Chapter Questions
Problem 8.32E
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How many moles of PCl5 will be produced if .331 moles of P4 is reacted with an excess of Cl using the following equation?

P4(s)+10Cl2(g) > 4PCI5(g)

Part A
How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation.
P4(s) + 10 Cl2(g) → 4 PCI5(g)
1.655 mol
662 mol
.331 mol
1.324 mol
.993 mol
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Transcribed Image Text:Part A How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation. P4(s) + 10 Cl2(g) → 4 PCI5(g) 1.655 mol 662 mol .331 mol 1.324 mol .993 mol Submit Request Answer Provide Feedback Type here to search
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