Part A Element X has successive ionization energies of 738 kJ/mol, 1451 kJ/mol, and 7733 kJ/mol. Element Z has successive ionization energies of 1000 kJ/mol, 2252 kJ/mol, and 3357 kJ/mol. What are the possible identities of X and Z? O x could be Mg, since its third ionization energy is so large. Z could be S, since its ionization energies are large and keep going up in regular intervals. O x could be P, since the third ionization energy is so large. Z could be Na, since its ionization energies keep going up in regular intervals. O x could be Na, since the second and third ionization energies are so much larger than the first one. Z could be a noble gas, since its ionization energies are large and keep going up in regular intervals. O x could be Fe, since its third ionization energy is so large. Z could be H since its ionization energies keep going up in regular intervals. Submit Request Answer
Part A Element X has successive ionization energies of 738 kJ/mol, 1451 kJ/mol, and 7733 kJ/mol. Element Z has successive ionization energies of 1000 kJ/mol, 2252 kJ/mol, and 3357 kJ/mol. What are the possible identities of X and Z? O x could be Mg, since its third ionization energy is so large. Z could be S, since its ionization energies are large and keep going up in regular intervals. O x could be P, since the third ionization energy is so large. Z could be Na, since its ionization energies keep going up in regular intervals. O x could be Na, since the second and third ionization energies are so much larger than the first one. Z could be a noble gas, since its ionization energies are large and keep going up in regular intervals. O x could be Fe, since its third ionization energy is so large. Z could be H since its ionization energies keep going up in regular intervals. Submit Request Answer
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Part A
Element X has successive ionization energies of 738 kJ/mol, 1451 kJ/mol, and 7733 kJ/mol. Element Z has successive ionization energies of 1000 kJ/mol, 2252 kJ/mol, and 3357 kJ/mol. What are the possible identities of X and Z?
O x could be Mg, since its third ionization energy is so large. Z could be S, since its ionization energies are large and keep going up in regular intervals.
O x could be P. since the third jonization energy is so large, Z could be Na, since its ionization energies keep going up in regular intervals.
O x could be Na, since the second and third ionization energies are so much larger than the first one. Z could be a noble gas, since its ionization energies are large and keep going up in regular intervals
O x could be Fe, since its third ionization energy is so large. Z could be H since its ionization energies keep going up in regular intervals.
Submit
Request Answer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7d7c266-9e7f-4a5c-8de7-55b89f8e3b4f%2Fd53e81bd-c8b2-4d57-b8b0-1925ae218e7f%2Fjwpl1zs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part A
Element X has successive ionization energies of 738 kJ/mol, 1451 kJ/mol, and 7733 kJ/mol. Element Z has successive ionization energies of 1000 kJ/mol, 2252 kJ/mol, and 3357 kJ/mol. What are the possible identities of X and Z?
O x could be Mg, since its third ionization energy is so large. Z could be S, since its ionization energies are large and keep going up in regular intervals.
O x could be P. since the third jonization energy is so large, Z could be Na, since its ionization energies keep going up in regular intervals.
O x could be Na, since the second and third ionization energies are so much larger than the first one. Z could be a noble gas, since its ionization energies are large and keep going up in regular intervals
O x could be Fe, since its third ionization energy is so large. Z could be H since its ionization energies keep going up in regular intervals.
Submit
Request Answer
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