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Below are the first seven ionization energies for a third period element. To which element do these ionization energies belong?

Below are the first seven ionization energies for a third period element. To which element do these ionization energies belong?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Ionization Energies of a Third Period Element** **Introduction:** In this exercise, we are looking at the first seven ionization energies of a particular third period element. The challenge is to determine which element these energies correspond to. **Ionization Energies:** - \( IE_1 \) = 1012 kJ/mol - \( IE_2 \) = 1903 kJ/mol - \( IE_3 \) = 2912 kJ/mol - \( IE_4 \) = 3956 kJ/mol - \( IE_5 \) = 6273 kJ/mol - \( IE_6 \) = 22233 kJ/mol - \( IE_7 \) = 27106 kJ/mol **Options:** A. Boron (B) B. Silicon (Si) C. Nitrogen (N) D. Phosphorus (P) E. Sulfur (S) **Explanation:** When determining the element based on ionization energies, it is crucial to observe the significant increase between energies, which often indicates the removal of an electron from a more stable, inner shell. Compare these ionization energy patterns to known values for third period elements to identify the correct element.
Transcribed Image Text:**Ionization Energies of a Third Period Element** **Introduction:** In this exercise, we are looking at the first seven ionization energies of a particular third period element. The challenge is to determine which element these energies correspond to. **Ionization Energies:** - \( IE_1 \) = 1012 kJ/mol - \( IE_2 \) = 1903 kJ/mol - \( IE_3 \) = 2912 kJ/mol - \( IE_4 \) = 3956 kJ/mol - \( IE_5 \) = 6273 kJ/mol - \( IE_6 \) = 22233 kJ/mol - \( IE_7 \) = 27106 kJ/mol **Options:** A. Boron (B) B. Silicon (Si) C. Nitrogen (N) D. Phosphorus (P) E. Sulfur (S) **Explanation:** When determining the element based on ionization energies, it is crucial to observe the significant increase between energies, which often indicates the removal of an electron from a more stable, inner shell. Compare these ionization energy patterns to known values for third period elements to identify the correct element.
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