Part 1 - Determining K, by lon Concentration 9.97 4.03 9.3325 x 10 pH of solution: pOH = 14-pH: JOH] = 100 Complete the following ICE table (using x): Kup Table Mg(OH) (s) Molarity: initial concentration 1 Change Equilibrium concentration Kup Table Molarity: initial concentration Change (-X 0.15580 MB (OH)2 My Complete the following ICE table (now using actual concentrations): Mg(OH), (8) Equilibrium concentration -5 11 Kip [Mg][OH]: Mg (aq) X X + 2 OH(aq) 0 2x 2x Mg (ag) + 2 OH (aq) To find K, use the above ICE table to find the concentration of Mg (you found the concentration of OH above using the pOH). Because there is a 1:2 stoichiometric ratio between Mg" and OH, [Mg] = [OH 1/2. Plug the values of [Mg] and [OH] into the K, expression below: ys 4

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Part 1 - Determining Kp by lon Concentration
9.92
4.03
9.3325 x 10
pH of solution:
pOH = 14-pH:
[OH] = 10:
Complete the following ICE table (using x):
Kup Table
Mg(OH); (s):
Molarity: initial
concentration
1
Change
Equilibrium
concentration
|-X
0.15589 MB (OH)2
Complete the following ICE table (now using actual concentrations):
Mg(OH), (8)
K, Table
Molarity: initial
concentration
Change
Equilibrium
concentration
Kip [Mg][OH]:
Mg (aq)
4
X
X
+ 2 OH(aq)
0
2x
Mg² (aq) +
2x
To find K, use the above ICE table to find the concentration of Mg" (you found the concentration of
OH above using the pOH). Because there is a 1:2 stoichiometric ratio between Mg" and OH, [Mg] =
[OH 1/2. Plug the values of [Mg] and [OH-] into the K, expression below:
2OH(aq)
Transcribed Image Text:Part 1 - Determining Kp by lon Concentration 9.92 4.03 9.3325 x 10 pH of solution: pOH = 14-pH: [OH] = 10: Complete the following ICE table (using x): Kup Table Mg(OH); (s): Molarity: initial concentration 1 Change Equilibrium concentration |-X 0.15589 MB (OH)2 Complete the following ICE table (now using actual concentrations): Mg(OH), (8) K, Table Molarity: initial concentration Change Equilibrium concentration Kip [Mg][OH]: Mg (aq) 4 X X + 2 OH(aq) 0 2x Mg² (aq) + 2x To find K, use the above ICE table to find the concentration of Mg" (you found the concentration of OH above using the pOH). Because there is a 1:2 stoichiometric ratio between Mg" and OH, [Mg] = [OH 1/2. Plug the values of [Mg] and [OH-] into the K, expression below: 2OH(aq)
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