Determine the pH of a solution that is 0.075 M (CH3):N and 0.10 M (CH.) NHCI. The value of Kb for (CH.):N is 5.2 x 104. 1. 3 NEXT > Based on the given values, set up ICE table in order to determine the unknown. (CH:):N(aq) + H:O(1) OH (aq) +(CH:)»NH (aq) Initial (M) Change (M) Equilibriu m (M). RESET 0.075 0.10 5.2 x 104 +x +2x -X -2x 0.075 + x 0.075 - x 0.075 + 2x 0.075 - 2x 0.10 + x 0.10 - x 0.10 + 2x 0.10- 2x

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Chapter1: Chemical Foundations
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3: Based on the ice table and Alan expression determine the ph of the solution
Determine the pH of a solution that is 0.075 M (CHs):N and 0.10
M (CH:) NHCI. The value of Kb for (CH:):N is 5.2 x 104.
NEXT >
Based on the given values, set up ICE table in order to determine the
unknown.
(CH:).N(aq)
H2O(1)
OH (aq)
+(CH:).NH (aq)
Initial (M)
Change
(M).
Equilibriu
m (M)
RESET
0.075
0.10
5.2 x 104
+x
+2x
-x
-2x
0.075 + x
0.075 - x
0.075 + 2x
0.075 - 2x
0.10 + x
0.10 - x
0.10 + 2x
0.10 - 2x
Transcribed Image Text:Determine the pH of a solution that is 0.075 M (CHs):N and 0.10 M (CH:) NHCI. The value of Kb for (CH:):N is 5.2 x 104. NEXT > Based on the given values, set up ICE table in order to determine the unknown. (CH:).N(aq) H2O(1) OH (aq) +(CH:).NH (aq) Initial (M) Change (M). Equilibriu m (M) RESET 0.075 0.10 5.2 x 104 +x +2x -x -2x 0.075 + x 0.075 - x 0.075 + 2x 0.075 - 2x 0.10 + x 0.10 - x 0.10 + 2x 0.10 - 2x
Subm
Determine the pH of a solution that is 0.075 M (CH3);N and 0.10
M (CH:):NHCI. The value of Kb for (CH:)sN is 5.2 x 104.
( PREV
1
3.
NEXT >
Based on your ICE table and definition of Kb, set up the expression for Kb in
order to determine the unknown. Do not combine or simplify terms.
Kp
5.2 x 10 4
RESET
[0]
[0.075]
[0.10]
[5.2 x 10]
[x]
[2x]
[2x}*
[0.075 + x]
[0.075 - x]
[0.075 + 2x]
[0.075 - 2x]
[0.10 + x]
[0.10 - x]
[0.10 + 2x]
[0.10 - 2x]
Transcribed Image Text:Subm Determine the pH of a solution that is 0.075 M (CH3);N and 0.10 M (CH:):NHCI. The value of Kb for (CH:)sN is 5.2 x 104. ( PREV 1 3. NEXT > Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine the unknown. Do not combine or simplify terms. Kp 5.2 x 10 4 RESET [0] [0.075] [0.10] [5.2 x 10] [x] [2x] [2x}* [0.075 + x] [0.075 - x] [0.075 + 2x] [0.075 - 2x] [0.10 + x] [0.10 - x] [0.10 + 2x] [0.10 - 2x]
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