**Equilibrium Calculation Problem** **Date:** 10/19/21 **Score:** 75% --- **Given the following reactions:** 1. \(2C \rightarrow D \) \(K_C = 8.53 \times 10^{-4}\) 2. \(D \rightarrow 2A + 2B \) \(K_C = 4.52 \times 10^{-2}\) **2nd Attempt** **Task:** Calculate the value of the equilibrium constant for the following reaction: \[ A + B \rightarrow C \] **Answer:** \[ K_C = \_ \times 10^{\_} \] **Progress:** 7 of 10 questions completed. Current Question: 7/10 **Interface:** Option to view solution.

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**Equilibrium Calculation Problem**

**Date:** 10/19/21  
**Score:** 75%

---

**Given the following reactions:**

1. \(2C \rightarrow D \)  
   \(K_C = 8.53 \times 10^{-4}\)

2. \(D \rightarrow 2A + 2B \)  
   \(K_C = 4.52 \times 10^{-2}\)

**2nd Attempt**

**Task:**

Calculate the value of the equilibrium constant for the following reaction:

\[ A + B \rightarrow C \]

**Answer:**

\[ K_C = \_ \times 10^{\_} \]

**Progress:**

7 of 10 questions completed.  
Current Question: 7/10  

**Interface:**

Option to view solution.
Transcribed Image Text:**Equilibrium Calculation Problem** **Date:** 10/19/21 **Score:** 75% --- **Given the following reactions:** 1. \(2C \rightarrow D \) \(K_C = 8.53 \times 10^{-4}\) 2. \(D \rightarrow 2A + 2B \) \(K_C = 4.52 \times 10^{-2}\) **2nd Attempt** **Task:** Calculate the value of the equilibrium constant for the following reaction: \[ A + B \rightarrow C \] **Answer:** \[ K_C = \_ \times 10^{\_} \] **Progress:** 7 of 10 questions completed. Current Question: 7/10 **Interface:** Option to view solution.
Expert Solution
Step 1

The reaction is said to be in equilibrium when the rate of forward reaction becomes equal to the rate of backward reaction.

Equilibrium constant Kc is the ratio of rate constant of forward reaction, Kf to rate constant of backward reaction, Kb.

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