Part 1: Calculate the specific heat of Bronze using coffee cup calorimeter. Bronze Data Mass Of Metal (Bronze) Ttmetal) Mass Of Water Tie120) Tawater & metal) (5 pts) 19.9797 g 200 °C 150.00 g 25.00 °C 27.32 °C Calculations: You must show ALL work here. 1. Calculate qu20 Qn,0 = mH,0 x SH,0 × AT Qn;0 = 2. Calculate the specific heat of Bronze. Qn,0 = -qmetal = 4metal = mmetal x SHH,0 x ATmetal 9metal (massmetat X AT) (19.9797 g x (27.32 – 200.00)°C) SHmetal SHmetal g°C 3. % error Calculation (the true value for SHbronze is 0.435 g°C

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Title: Calculating the Specific Heat of Bronze Using a Coffee Cup Calorimeter**

**Introduction**

Understanding specific heat is crucial in material science and thermodynamics. In this tutorial, we will calculate the specific heat of bronze using a coffee cup calorimeter. Let's start with the necessary data and formulas, followed by detailed steps for calculations.

---

**Data Table: Bronze Data (5 pts)**

| Parameter                | Value          |
|--------------------------|----------------|
| Mass of Metal (Bronze)   | 19.9797 g      |
| Temperature of Metal (\(T_{\text{metal}}\)) | 200°C           |
| Mass of Water            | 150.00 g       |
| Temperature of Water (\(T_{\text{H2O}}\)) | 25.00°C         |
| Final Temperature (\(T_{\text{water & metal}}\)) | 27.32°C         |

---

**Calculations**

*You must show all work here.*

1. **Calculate \(Q_{\text{H2O}}\)**

   Formula: 
   \[
   Q_{\text{H2O}} = m_{\text{H2O}} \times SH_{\text{H2O}} \times \Delta T
   \]
   Where \(Q_{\text{H2O}}\) is the heat absorbed by water, \(m_{\text{H2O}}\) is the mass of water, \(SH_{\text{H2O}}\) is the specific heat of water, and \(\Delta T\) is the change in temperature.

2. **Calculate the Specific Heat of Bronze**

   The formula for the heat balance:
   \[
   Q_{\text{H2O}} = -Q_{\text{metal}}
   \]
   This implies:
   \[
   q_{\text{metal}} = m_{\text{metal}} \times SH_{\text{H2O}} \times \Delta T_{\text{metal}}
   \]
   *Specific Heat of Metal (\(SH_{\text{metal}}\)):*
   \[
   SH_{\text{metal}} = \frac{q_{\text{metal}}}{m_{\text{metal}} \times \Delta T} = \frac{19.9797 \, \text{g} \times (27.32 - 200.00)°C}{J/g°C}
   \]

3. **%
Transcribed Image Text:**Title: Calculating the Specific Heat of Bronze Using a Coffee Cup Calorimeter** **Introduction** Understanding specific heat is crucial in material science and thermodynamics. In this tutorial, we will calculate the specific heat of bronze using a coffee cup calorimeter. Let's start with the necessary data and formulas, followed by detailed steps for calculations. --- **Data Table: Bronze Data (5 pts)** | Parameter | Value | |--------------------------|----------------| | Mass of Metal (Bronze) | 19.9797 g | | Temperature of Metal (\(T_{\text{metal}}\)) | 200°C | | Mass of Water | 150.00 g | | Temperature of Water (\(T_{\text{H2O}}\)) | 25.00°C | | Final Temperature (\(T_{\text{water & metal}}\)) | 27.32°C | --- **Calculations** *You must show all work here.* 1. **Calculate \(Q_{\text{H2O}}\)** Formula: \[ Q_{\text{H2O}} = m_{\text{H2O}} \times SH_{\text{H2O}} \times \Delta T \] Where \(Q_{\text{H2O}}\) is the heat absorbed by water, \(m_{\text{H2O}}\) is the mass of water, \(SH_{\text{H2O}}\) is the specific heat of water, and \(\Delta T\) is the change in temperature. 2. **Calculate the Specific Heat of Bronze** The formula for the heat balance: \[ Q_{\text{H2O}} = -Q_{\text{metal}} \] This implies: \[ q_{\text{metal}} = m_{\text{metal}} \times SH_{\text{H2O}} \times \Delta T_{\text{metal}} \] *Specific Heat of Metal (\(SH_{\text{metal}}\)):* \[ SH_{\text{metal}} = \frac{q_{\text{metal}}}{m_{\text{metal}} \times \Delta T} = \frac{19.9797 \, \text{g} \times (27.32 - 200.00)°C}{J/g°C} \] 3. **%
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