2. The hydrogenation of coal is a method of producing methane by the following reaction: Ca + 2H2@) → CH«2 AH = ? Find the AH by using the enthalpy changes in the following combustion reactions. Ca + Oze → CO22 Hze + ½ Oze → H2O@ CH2 + 202e → CO2e + 2H20M AH =- 394 kJ AH =- 286 kJ AH =- 891 kJ

2. The hydrogenation of coal is a method of producing methane by the following reaction: Ca + 2H2@) → CH«2 AH = ? Find the AH by using the enthalpy changes in the following combustion reactions. Ca + Oze → CO22 Hze + ½ Oze → H2O@ CH2 + 202e → CO2e + 2H20M AH =- 394 kJ AH =- 286 kJ AH =- 891 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

What is the enthalpy change when 2.00 mol of oxygen (O2) react? C12H22O11(s) + 12 O2(g) → 12 CO2(g) + 11 H2O(l) ΔH = -5644 kJ
Given that enthalpy of formation of the several compounds: C(s)+O2(g)>CO2(g);AH=-393.5kJ S(s)+O2(g)→SO2(g);AH=-296.8kJ C(s)+2S(s)→CS2(1);AH=+87.9 kJ Determine the enthalpy of combustion reaction of carbon disulfide!
Consider the reaction: NH,NO3(s) → N20(g) + H2O(1) AH° rxn = -127.49kJ Calculate the enthalpy of formation of N20 based on the following enthalpy values: NHẠNO3(s) = -330 kJ/mol H20(1)= -285.8 kJ/mol
9
Consider these reactions: AH = -184.6 kJ Reaction 1: H₂(g) + Cl₂ (g) → 2HCl(g) Reaction 2: 20F2 (g) → O2 (g) + 2 F₂(g) ▲H = −49.4 kJ Reaction 3: N₂(g) + 2O2(g) → 2NO₂(g) AH = +66.4 kJ Use Reaction 3. How much energy (in kJ) is absorbed when 104. L of nitrogen dioxide is created at STP? Round to the nearest whole number. Answer:
10. Calculate the standard enthalpy for the reaction: 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), given the following data: N2(g) + O2(g) → 2NO(g) ΔHrxn = -43.1 kcal mol-1 N2(g) + 3H2(g) → 2NH3(g) ΔHrxn = -21.9 kcal mol-1 2H2(g) + O2(g) → 2H2O(g) ΔHrxn = -115.6 kcal mol-1
Given the following reactions: N2 (g) + O2 (g) → 2NO (g) AH = +180.7 kJ 2N20 (g) → O2 (g) + 2N2 (g) AH = -163.2 kJ the enthalpy of reaction for 2N20 (g) → 2NOo (g) + N2 (g) is kJ. -343.9 343.9 -145.7 145.7 O 17.5
Calculate AH for the reaction P4010(s) + 6PC15(g) – 10C13PO(g) given, P4(s) + 6C12(g) → 4PC13(g) AH = -1225.6 kJ P4(s) + 502(g) – P4010(s) AH = -2967.3 kJ PC13(g) + Cl2(g) → PC15(g) AH = -84.2 kJ PC13(g) + (1/2)02(g) – C13PO(g) AH=-285.7 kJ ΔΗ- kJ
1. The enthalpy changes of the following reactions Can be measured: Co H. (g) + 7/2 Q₂ (g) → 2 CO₂ (g) + 3 H ₂ O ( ) соно A₁ H° = - 1428.7 KJ/mol-rxn f C₂ H ₂ OH (g) + 3 Q₂ (g) →) 2 CO₂ (g) + 3 H ₂ O (g) Arto= ° = -1277 kJ/mol-rxn a Use these values and Hess's law to determine the for the reaction. ½/2 C ₂ H 6 (g) + ½z O₂ (g) → C₂ H₂ OH (g) en On thalpy chang ks/mol-cox Enthalpy Change = 000 20 * LANCEEL
The flame in a torch used to cut metal is produced by burning acetylene (C2H2)(26.04 g/mol) in pure oxygen. Assuming the combustion of 1 mole of acetylene releases 1251 kJ of heat, what mass of acetylene is needed to cut through a piece of steel if the process requires 22.5 × 104 kJ of heat? 2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(g) ΔH = –2502 kJ
When 3.8 g A are reacted with 8.5 g D, according to the balanced chemical equation below, 33 kJ of energy are released. Please calculate the enthalpy for this reaction when 3 moles of G are produced. 2A + 3D = 2Z + 3G given molar masses: A = 141.8 g/mole D = 63.996 g/ mole Z = 4.032 g/ mole G = 56.028 g/ mole
7