(1) Calculate the heat capacity (Ccal) for the calorimeter done in the lab, part 4. All of the heat leaving the hot water will go into either into the cold water or the coffee cup calorimeter. Be cautious about the signs. The q for the hot water is negative (heat leaving the system) and the q for the cold value for your calorimeter. You will get the heat capacity by multiplying the specific heat of the substance by water and cup will be positive (heat entering the cold water and cup). The calorimeter constant is a fixed its mass. The specific heat (Cs) of water is 4.184 J/g C = -Qhot cold + acup Ccup = [masShot X CSwater X AT hot ]-[mass cold X CS water X AT cold] AT cold Solve for Ccup. Show your work below. It should be around 10-30 J/°C for your calorimeter.
(1) Calculate the heat capacity (Ccal) for the calorimeter done in the lab, part 4. All of the heat leaving the hot water will go into either into the cold water or the coffee cup calorimeter. Be cautious about the signs. The q for the hot water is negative (heat leaving the system) and the q for the cold value for your calorimeter. You will get the heat capacity by multiplying the specific heat of the substance by water and cup will be positive (heat entering the cold water and cup). The calorimeter constant is a fixed its mass. The specific heat (Cs) of water is 4.184 J/g C = -Qhot cold + acup Ccup = [masShot X CSwater X AT hot ]-[mass cold X CS water X AT cold] AT cold Solve for Ccup. Show your work below. It should be around 10-30 J/°C for your calorimeter.
Chemistry
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Chapter1: Chemical Foundations
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![(1) Calculate the heat capacity (Ccal) for the calorimeter done in the lab, part 4.
All of the heat leaving the hot water will go into either into the cold water or the coffee cup calorimeter. Be
cautious about the signs. The q for the hot water is negative (heat leaving the system) and the q for the cold
value for your calorimeter. You will get the heat capacity by multiplying the specific heat of the substance by
water and cup will be positive (heat entering the cold water and cup). The calorimeter constant is a fixed
its mass. The specific heat (Cs) of water is 4.184 J/g C
=
-Qhot cold + acup
Ccup
=
[masShot X CSwater X AT hot ]-[mass cold X CS water X AT cold]
AT cold
Solve for Ccup. Show your work below. It should be around 10-30 J/°C for your calorimeter.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fadcb027d-732c-486e-b0c8-f9f0ef7820b1%2F4e1dd79a-b1ba-4704-b82a-5726a709da41%2Faerzns5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(1) Calculate the heat capacity (Ccal) for the calorimeter done in the lab, part 4.
All of the heat leaving the hot water will go into either into the cold water or the coffee cup calorimeter. Be
cautious about the signs. The q for the hot water is negative (heat leaving the system) and the q for the cold
value for your calorimeter. You will get the heat capacity by multiplying the specific heat of the substance by
water and cup will be positive (heat entering the cold water and cup). The calorimeter constant is a fixed
its mass. The specific heat (Cs) of water is 4.184 J/g C
=
-Qhot cold + acup
Ccup
=
[masShot X CSwater X AT hot ]-[mass cold X CS water X AT cold]
AT cold
Solve for Ccup. Show your work below. It should be around 10-30 J/°C for your calorimeter.
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