Surgical complications: A medical researcher wants to construct a 99.9% confidence interval for the proportion of knee replacement surgeries that result incomplications.Part: 0/2ontinuePart 1 of 2(a) An article in a medical journal suggested that approximately 16% of such operations result in complications. Using this estimate, what sample size isneeded so that the confidence interval will have a margin of error of 0.04?A sample of operations is needed to obtain a 99.9% confidence interval with a margin of error of 0.04 using theestimate 0.16 for p.Part: 1 / 2Part 2 of 2(b) Estimate the sample size needed if no estimate of p is available.A sample of operations is needed to obtain a 99.9% confidence interval with a margin of error of 0.04 when noestimate of p is available.XXSŚ

It is given that Confidence level = 99.9%Margin of error, E = 0.04

Answered: Part: 0/2 Part 1 of 2 (a) An article in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Two population means are being compared. A sample from population 1 yields data: {105.1, 123.7, 112.5, 107.9, 132.1}. A sample from the population 2 yields data: {125.1, 131.2, 138.9}. Construct a 95% confidence interval for the difference in means, mean of population 2 minus mean of population 1: -Hi• Assume each population is normally distributed. Use the Welch-Saterthwaite t-distribution degrees of freedom. Enter the upper (right) endpoint for the confidence interval.
"A company produces resistors by the thousands, and Gerry is in charge of quality control. He picks 26 resistors at random as a sample, and calculates the sample mean x = 7.268 kOhms and sample standard deviation S = 0.2142 kOhms. Calculate the confidence interval as a (+/-) value to 65% confidence level."
Hip surgery: In a sample of 118 hip surgeries of a certain type, the average surgery time was 135.9 minutes with a standard deviation of 22.1 minutes. Part: 0 / 2 0 of 2 Parts Complete Part 1 of 2 (a) Construct a 99% confidence interval for the mean surgery time for this procedure. Round your answers to one decimal place. A 99% confidence interval for the mean surgery time for this procedure is <<μ .
a sample size n=99 is drawn from a population whose standard deaviation is 11 (a) find the margin of error for a confidence interval for u (population mean). round the answer to at least three decimal places the margin of error for a 90% confidence for u (population mean) is
Only typed answer
Is the birth rate of the infants in this sample significantly different from that of the general population at alpha level of 0.05? Explain your response.
Pain after surgery: In a random sample of 54 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 94 patients undergoing a new procedure, only 16 required pain medication. Part: 0/ 2 Part 1 of 2 (a) Construct a 99% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Let p, denote the proportion of patients who had the old procedure needing pain medication. OL Use tables to find the critical value and round the answer to at least three decimal places. A 99% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures is
Age x and resting heart rate y were sampled for 25 randomly selected children from age 2 to 9. Summary information is: n = 25, Σx = 140.5, Σx2 = 903.75, Σy = 2567, Σy2 = 264, 457, Σxy = 14, 171.5 (a) Compute a 95% confidence interval for the average resting heart rate of 3 six year old children.
8.1 Confidence Interval 1. Crop researchers are interested in the productivity of a new variety of corn. They plant 25 plots with randomly selected seeds of the new variety, record the yield in bushels per acre, and find that a 99% confidence interval for the true mean yield is 118 to 130 bushels per acre. (a) Interpret the confidence interval. (b) What is the point estimate that was used to create the interval? What is the margin of error? (c) Interpret the confidence level. (d) Based on the research, a marketer tells a possible customer that with this new variety of corn they can expect to receive more than 130 bushels per acre, on average. Use the confidence interval to evaluate this statement.
What critical value of t* should be used for a 99.5% confidence interval for the population mean based upon a random sample of 18 observations? Find the t-table here. t* = 2.878 t* = 2.898 t* = 3.197 t* = 3.222
A random sample of 250 SCC students yields 79 full-timers and 171 part-timers. (a)Construct a 90% confidence interval for the overall proportion of full-time students at SCC.(b)The margin of error associated with the above c.i. is_____(c)How large a sample should be selected if we want the margin of error to be 2 percentage points?

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