ifetime of electronics: In a simple random sample of 100 electronic components produced by a certain method, the mean20fetime was 125 hours. Assume that component lifetimes are normally distributed with population standard deviation o =ours, Round the critical value to no less than three decimal places.Part 1 of 2(a) Construct an 80% confidence interval for the mean battery life. Round the answer to the nearest whole number.An 80% confidence interval for the mean battery life is 122 < µ < 128Part: 1 / 2Part 2 of 2(b) Find the sample size needed so that a 90% confidence interval will have a margin of error of 3.A sample size ofis needed so that a 90% confidence interval will have a margin of errorof 3. Round the sample size up to the nearest integer.Save For LaterSubmit AssignmeCheck Answer2022 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Ce

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You measure the blackbody temperature of the night sky three times and read: 7.3C, 9.1C, and 8.7C. Assuming the temperature fluctuation is due to your device, how should you represent this result with its associated error if we assume a 95% confidence interval? Does the standard deviation of a population change dramatically as more data comes in? Standard error? How might we use a low-precision device to make a precise measurement of some natural constant like the speed of light in a vacuum? The mean of a data set is 3.45 and the standard error is 0.003. How should the result be written using a 95% confidence interval?
Create a 85% confidence interval for a population mean from a sample of size 46 with sample mean i = 4.5. The population standard deviation is known to be o = 0.77. [three decimal accuracy] [three decimal accuracy]
A random sample of 5 fields of rye has a mean yield of 21.3 bushels per acre and standard deviation of 2.53 bushels per acre. Determine the 99 % confidence interval for the true mean yield. Assume the population is approximately normal. Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Mrs. Gallas wanted to estimate the average weight of an Oreo cookie to determine if theaverage weight was less than advertised. She selected a random sample of 30 cookies andfound the weight of each cookie (in grams). The mean weight was = 11.1921 grams with astandard deviation of sx = 0.0817 grams. Make a 95% confidence interval to estimate the truemean weight of an Oreo. 1. What is the formula for calculating the standard deviation of the sampling distribution of x? 2.What condition must be met to use this formula? Has it been met?
The Mental Development Index (MDI) of the Bayley Scales of Infant Development is a standardized measure used in observing infants over time. It is approximately normal with a mean of 100 and a standard deviation of 16. Complete parts a through c. a. What proportion of children has an MDI of (i) at least 130? (ii) at least 90? (1) The proportion of children having an MDI of at least 130 is 0.0301 (Round to four decimal places as needed.) 2 (ii) The proportion of children having an MDI of at least 90 is 0.7357. (Round to four decimal places as needed.) b. Find the MDI score that is the 98th percentile. The 98th percentile MDI score is 132.8 (Round to two decimal places as needed.) c. Find the MDI score such that only 2% of the population has an index below it. View an example Get more help - W 2% of the population have an MDI score below. (Round to two decimal places as needed.) S X H mmand ای ایرانی 3 20 D C $ R F % 5 V 55 T G 스 6 B Y H & 44 F7 U N 8 Dil 1 M 9 K DD 19 O 1 L 9 F10 P…
If a Type I error is made, what conclusion will be drawn regarding the mean breaking strength?
A geologist examines 1414 geological samples for mercury concentration. The mean mercury concentration for the sample data is 0.4660.466 cc/cubic meter with a standard deviation of 0.04530.0453. Determine the 90%90% confidence interval for the population mean mercury concentration. Assume the population is approximately normal. Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
A random sample of 9 fields of rye has a mean yield of 37.0 bushels per acre and standard deviation of 6.23 bushels per acre. Determine the 95% confidence interval for the true mean yield. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
* Question Completion Status: OC. 0.0099 d. 0.0918 QUESTION 3 EPA fuel economy estimates for automobile models tested recently predicts a mean of 24 mpg and a standard deviation of 6 mpg. Assume that a Normal model applies, N(24, 6 ). What mpg for the automobiles would be the cutoff value for the lowest 10% of the mpg's (the 10th percentile of gas mileage)? O a. 12.80 mpg O b. 10.00 mpg O c. 31.38 mpg O d. 16.32 mpg QUESTION 4
A random sample of 27 fields of rye has a mean yield of 43.1 bushels per acre and standard deviation of 5.31 bushels per acre. Determine the 80% confidence interval for the true mean yield. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
A sample of n=41n=41 data values randomly selected from a normally distributed population has variance s2=30s2=30. Construct a 95% confidence interval for the population variance. Round your endpoints to one decimal place.
Step 3 The necessary value for Za/2 was determined to be 1.645. Recall the given information. Sample 1 n1 = 400 P1 = 0.56 P2 = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. P₁(1-P₁) P₂(1-P₂) 1 72 lower bound = P₁-P₂-²a/2 = 0.560.41 Sample 2 n2 = 300 = 0.0559 = 0.56 0.41 = 02441 X Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₁(1-P₁) P₂(1-P₂) upper bound = P₁ P₂ + ²a/2√ n1 n2 X + ✔ - 1.645, + 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 0.56(1 0.56) + 400 + 0.41(1 0.41) 300

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