Energy drinks: A survey of college students reported that in a sample of 402 male college students, the average number of energy drinks consumed per monthwas 2.41 with a standard deviation of 3.18, and in a sample of 390 female college students, the average was 1.50 with a standard deviation of 4.77.Part: 0/2Part 1 of 2Construct a 80% confidence interval for the difference between men and women in the mean number of energy drinks consumed. Let μ, denote the meannumber of energy drinks consumed by men. Use tables to find the critical value and round the answers to at least two decimal places.A 80% confidence interval for the difference between men and women in the mean number of energy drinks consumed is0<44-₂2 <0.XSPart: 1/2Part 2 of 2Based on the confidence interval, is it reasonable to believe that the mean number of energy drinks consumed may be the same for both male and femalecollege students?It (Choose one)reasonable to believe that the mean number of energy drinks consumed may be the same for both male and female collegest isis not

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Answered: I a sample of 402 male college…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The weights of a certain type of steer follow a Normal model with a mean weight of 1191 pounds and a standard deviation of 54 pounds. (Use 4 decimals for all answers below.)(a) What weight is required for a steer to be among the heaviest 10% of steers? (b) What weight is required for a steer to be among the lightest 25% of steers? (c) What is the IQR of these weights?
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A researcher collected sample data for 19 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 192.4, with a standard deviation of 8.2. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 90% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: Upper limit:
The mean score on a driving exam for a group of driver’s education students is 76 points, with a standard deviation of 6 points. Apply chebychev’s theorem to the data using K=2. Interpret, At least ___% of the exam score falls between ___and ____
A researcher collected sample data for 10middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 192.5, with a standard deviation of 9. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 95% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 95% confidence interval.Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. Lower Limit___ Upper Limit___
A researcher collected sample data for 19 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 190.3, with a standard deviation of 9.5. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 95% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit= Upper limit=
The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. Find a 99% confidence interval on the difference in the mean life. Car Brand 1 Brand 2 1 36,925 34,318 2 45,300 42,280 3 36,256 35.548 4 32,100 31,950 5 37,210 38,015 6 48,360 47,800 7 38.200 37,810 8 33,500 33,215 Round your answer to 2 decimal places. Do not use commas.
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Paramesan cheese is aged for an average of 24 months to allow it to develop the desire richness in flavor the standard deviation for the length of time Parmesan cheese is aged is 3.7 months How long would Parmesan cheese have to be aged in order to be in the 90th percentile? Assume that the data is normally distributed
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A researcher collected sample data for 10 women ages 18 to 24. The sample had a mean serum cholesterol level (measured in mg/100 mL) of 188.4, with a standard deviation of 5.7. Assuming that serum cholesterol levels for women ages 18 to 24 are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group. Then find the lower limit and upper limit of the 99% confidence interval.
A researcher collected sample data for 19 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 191.5, with a standard deviation of 6.5. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 95% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. lower limit ____ Upper Limit ____

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