Drill lifetime: A sample of 50 drills had a mean lifetime of 12.54 holes drilled when drilling a low-carbon steel. Assume the population standard deviation isEspañol7.11.Part 1 of 3(a) Construct a 95% confidence interval for the mean lifetime of this type of drill. Use tables or technology. Round your answers to at least two decimalplaces.The confidence interval is10.5714.51Part 2 of 3(b) The manufacturer of the drills claims that the mean lifetime is greater than 13. Does this confidence interval contradict this claim?Nothe confidence interval does not contain anyvalues greater than 13, so the claimis notcontradicted.Part: 2 / 3Part 3 of 3(c) How large would the sample need to be so that a 95% confidence interval would have a margin of error of 1.0?The sample size would need to be

(C) We have given that, Population standard deviation (σ) = 7.11, confidence interval = 95% and…

Answered: Part: 2 / 3 Part 3 of 3 (c) How large…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If n=520 and ˆpp^ (p-hat) = 0.4, construct a 98% Confidence Interval.In order to use technology, you need to compute the number of successes:x = n*ˆpp^Give your answers to three decimals. ________< p < __________
Question 3 Create a 90% confidence interval for a population proportion from a sample of size 84 with sample 46 proportion p 84 [three decimal accuracy] [three decimal accuracy] Submit Question a山T0 MAR 18 MacBook Air 80 F1 F2 F3 F4 F5 F6 F @ # $ 1 2 3 4 5
✓ 1 ✓ 2 Part: 0/2 Part 1 of 2 A sample of Skip Part 3 4 Check = 5 How's the economy? A pollster wants to construct an 80% confidence interval for the proportion of adults who believe that economic conditions are getting better. X 6 7 (a) A poll taken in July 2010 estimates this proportion to be 0.28. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.05? 8 R adults is needed to obtain an 80% confidence interval with a margin of error of 0.05. 9 MacBook Air 10 H X S Save For Later Español 8 8. Submit Assignment © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility
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A simple random sample with n = 55 provided a sample mean of 24.5 and a sample standard deviation of 4.4. (Round your answers to one decimal place.) (a) Develop a 90% confidence interval for the population mean. to (b) Develop a 95% confidence interval for the population mean. to (c) Develop a 99% confidence interval for the population mean. to (d) What happens to the margin of error and the confidence interval as the confidence level is increased? As the confidence level increases, there is a larger margin of error and a more narrow confidence interval. As the confidence level increases, there is a smaller margin of error and a wider confidence interval. As the confidence level increases, there is a larger margin of error and a wider confidence interval. As the confidence level increases, there is a smaller margin of error and a more narrow confidence interval.
8.1 Confidence Interval 1. Crop researchers are interested in the productivity of a new variety of corn. They plant 25 plots with randomly selected seeds of the new variety, record the yield in bushels per acre, and find that a 99% confidence interval for the true mean yield is 118 to 130 bushels per acre. (a) Interpret the confidence interval. (b) What is the point estimate that was used to create the interval? What is the margin of error? (c) Interpret the confidence level. (d) Based on the research, a marketer tells a possible customer that with this new variety of corn they can expect to receive more than 130 bushels per acre, on average. Use the confidence interval to evaluate this statement.
Question 4(a) A sample of test scores is obtained. The scores are displayed as follows:11, 16, 19, 15, 7, 8, 10Test the hypothesis that the mean score is 15 at 1% significance level (b) A chemical manufacturer is concerned about the degree of contamination in the raw materialshipments purchased from a supplier. Taking a random sample of 20 shipments of raw materials,the standard deviation of contamination is 3.59. Construct the 95% confidence interval forpopulation variance
Question 2 Tony’s Pizza guarantees all pizza deliveries within 30 minutes of the placement of orders. It is known that a preliminary study has shown that 93% of all Tony’s pizzas are delivered within 30 minutes. How large should the sample size be so that the 99% confidence interval for the population proportion has a margin of error of 0.02?
Boys and girls: The National Health Statistics Reports reported that a sample of 310 one-year-old boys had a mean weight of 25,3 pounds with a standard deviation of 3.3 pounds. In addition, a sample of 286 one-year-old girls had a mean weight of 24.3 pounds with a standard deviation of 3.6 pounds. Part: 0/2 Part 1 of 2 Construct a 98% confidence interval for the difference between the mean weights. Let u, denote the mean weight of one-year-old boys. Use the TI-84 plus calculator and round the answers to one decimal place. A 98% confidence interval for the difference between the mean weights is
You want to design a study to estimate the proportion of students on your campus who agree with the statement “The student government is an effective organization for expressing the needs of students to the administration.” You will use a 90% confidence interval and you would like the margin of error to be 0.05 or less. In previous years, it has been noted that the 32% of the campus agree with the statement. The minimum sample size required is approximately (A) 22 (B) 1795 (C) 335 (D) 236 If you feel the answer is none of the choices given, submit no answer to the question.
Boys and girls: The National Health Statistics Reports reported that a sample of 320 one-year-old boys had a mean weight of 24.9 pounds with a standard deviation of 3.2 pounds. In addition, a sample of 296 one-year-old girls had a mean weight of 23.6 pounds with a standard deviation of 3.6 pounds. Part: 0 / 2 Part 1 of 2 Construct a 90% confidence interval for the difference between the mean weights. Let μ₁ denote the mean weight of one-year-old boys. Use the TI-84 plus calculator and round the answers to one decimal place. A 90% confidence interval for the difference between the mean weights is

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Part: 2 / 3 Part 3 of 3 (c) How large would the sample need to be so that a 95% confidence interval would have a margin of error of 1.0? The sample size would need to be