Pain after surgery: In a random sample of 55 patients undergoing a standard surgical procedure, 20 required medication for postoperative pain. In a random sample of 92 patients undergoing a new procedure, only 18 required pain medication. Part: 0/ 2 Part 1 of 2 (a) Construct a 95% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Let p, denote the proportion of patients who had the old procedure needing pain medication. Use tables to find the critical value and round the answer to at least three decimal places. A 95% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures is
Q: Before After 6.9 6.3 3.6 2.1 7.3 7.1 12.8 8.6 8.5 8.2 10.1 6.4 8.4 3.9 5.2 2.1
A: We find the differences of ‘before’ and ‘after’. di= Xi-Yi
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A: n1=80n2=100 x1=32x2=14 p1=3280=0.4 p2=14100=0.14 q1=1-p1=1-0.4=0.6 q2=1-p2=1-0.14=0.86
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A: We have given that Sample size n = 420092 Favorable cases x = 131 Sample proportion p^=x/n
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A: (a)
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A: sample size(n)=420098sample proportion()=0.0324%=0.000324
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A: We have given that Sample size n=420100 Sample proportion p^= 0.000329 95% confidence interval
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A: Let P₁ denote the proportion of patients who had the old procedure needing pain medication.
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A: Givenn1=51x1=22p1^=x1n1=2251=0.4314n2=88x2=16p2^=x2n2=1688=0.1818Confidence interval = 99.5%
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- In a random sample of 392 people that were tested for the Norcovirus, it was found that 314 did not have the virus. A 97% confidence interval was constructed to estimate the proportion of the population that does not have the Norcovirus. This confidence interval came out to be (0.76,0.84).8. Forty-eight people were randomly assigned to a treatment or a control group. The stats for the treatment group (n1 = 24) are X = 21, Si= 25. The results for the control group (n2 = 24) are X2 = 18, S3=64. Test the hypothesis that the treatment mean is greater than the control mean. List null and alternative hypotheses, rejection region & critical value, compute test statistic, and interpret results.A random sample of 328 medical doctors showed that 171 had a solo practice. Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate ?̂ for p, also find a 95% confidence interval for p.
- In an engineering class, students want to determine the difference in the mean strength between two different types of building materials—Type A, which is relatively inexpensive, and Type B, which is slightly more expensive. The students take a random sample of 60 of the Type A building material and a random sample of 27 of the Type B building material. Given the mean strength for each sample, the students construct a 95% confidence interval for the difference in population means. (a) Determine the degrees of freedom for the conservative approach for finding the t critical value. (b) Find the t critical value associated with 95% confidence. (Use a table or SALT. Round your answer to two decimal places.)A study of 420,073 cell phone users found that 136 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0326% for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. D%In a survey of 1076 adults, a poll asked, "Are you worried or not worried about having enough money for retirement?" Of the 1076 surveyed, 551 stated that they were worried about having enough money for refirement. Construcd a 99% confidence interval for the proportion of adults who are worried about having enough money for retirement. A 99% confidence interval for the proportion of adults who are worried about having enough money for retirement is ( (Use ascending order. Round to four decimal places as needed) Question Help Enter your answer in each of the answer boxes. P Type here to search 4 00 ENG 414/2021 DELL F12 VYZ Priscr Delehes Seers F10 FO F7 F2 FS Esc F1 Fa SAL 40 BackspuMA %23 5S 13 T R Tab 10 Enter K D F S A S Caps Lock Shift Ctri Alt Alt Fr CtriFor a study on the current trend in the design of social robots, researchers obtained a random sample of 103 social robots through a Web search and determined that 63 were designed with legs, but no wheels. Complete parts a and b. a. Find a 90% confidence interval for the proportion of all social robots designed with legs, but no wheels. Interpret the result.2 different treatments were used to speed the relief time (in minutes) of migraines. 8 subjects received each treatment. The recovery times are listed below. Treatment 1: 20 19 29 25 34 32 39 38 Treatment 2: 18 18 16 17 29 28 21 37 Construct a 90% confidence interval for the difference in the relief time between the 2 treatments.Pain after surgery: In a random sample of 54 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 94 patients undergoing a new procedure, only 16 required pain medication. Part: 0/ 2 Part 1 of 2 (a) Construct a 99% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Let p, denote the proportion of patients who had the old procedure needing pain medication. OL Use tables to find the critical value and round the answer to at least three decimal places. A 99% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures isA study of 420 comma 026 cell phone users found that 140 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0434 % for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. b. Do cell phone users appear to have a rate of cancer of the brain or nervous system that is different from the rate of such cancer among those not using cell phones? Why or why not?A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?A study is comparing the taste of instant coffee with fresh-brewed coffee. 50 individuals(random;y sampled) take part in the study. Each individual tastes both kinds of coffee, and declares which kind he or she prefers. The order in which the two kinds of coffee are given to each individual is randomized. 32 individuals in the sample prefer the fresh-brewed coffee. Use a suitable normal approximation to find a 95% confidence interval for the proportion of all individuals who would prefer fresh-brewed coffee. What is the lower limit of this confidence interval?SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. 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