A study of 420,098 cell phone users found that 0.0324% of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0335% for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system %
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![A study of 420,098 cell phone users found that 0.0324% of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the
rate of such cancer was found to be 0.0335% for those not using cell phones. Complete parts (a) and (b).
a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous
system
Do not round until the final answer. Then round to three decimal places as needed.]
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- A study of 420,007 cell phone users found that 136 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0319% for those not using cell phones. Complete parts (a) and (b). Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. b. Do cell phone users appear to have a rate of cancer of the brain or nervous system that is different from the rate of such cancer among those not using cell phones? Why or why not?A study of 420,016 cell phone users found that 130 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0318% for those not using cell phones. Complete parts (a) and (b) a)use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. ____% < p < ____% b)do cell phone users appear to have a rate of cancer of the brain or nervous system that is different from the rate of such cancer among those not using cell phones. Why or why not? a) Yes, because 0.0318% is not included in the confidence interval b) Yes, because 0.0318% is included in the confidence interval c) No, because 0.0318% is not included in the confidence interval d) No, because 0.0318% is included in the confidence intervalAllen's hummingbird has been studied by zoologist Bill Alther. Suppose a small group of 10 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x=3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with o=0.36 gram. find an 80% confidence interval for the average weights of Allen's hummingbirds in the study religion. What is the margin of error? (Round your answers to two decimal places) lower limit= upper limit=
- study of 420,077 cell phone users found that 133 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0236% for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system.A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a 95% confidence interval for the proportion of adults who have a Facebook page.A poll reported that only 1316 out of a total of 1746 adults in a particular region said they had a "great deal of confidence" or "quite a lot of confidence" in the military. Assume the conditions for using the CLT are met. Complete part (a) (a) Find a 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the military, and interpret this interval. The 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the military is: ( ? , ? )
- In an engineering class, students want to determine the difference in the mean strength between two different types of building materials—Type A, which is relatively inexpensive, and Type B, which is slightly more expensive. The students take a random sample of 60 of the Type A building material and a random sample of 27 of the Type B building material. Given the mean strength for each sample, the students construct a 95% confidence interval for the difference in population means. (a) Determine the degrees of freedom for the conservative approach for finding the t critical value. (b) Find the t critical value associated with 95% confidence. (Use a table or SALT. Round your answer to two decimal places.)In a survey of 1076 adults, a poll asked, "Are you worried or not worried about having enough money for retirement?" Of the 1076 surveyed, 551 stated that they were worried about having enough money for refirement. Construcd a 99% confidence interval for the proportion of adults who are worried about having enough money for retirement. A 99% confidence interval for the proportion of adults who are worried about having enough money for retirement is ( (Use ascending order. Round to four decimal places as needed) Question Help Enter your answer in each of the answer boxes. P Type here to search 4 00 ENG 414/2021 DELL F12 VYZ Priscr Delehes Seers F10 FO F7 F2 FS Esc F1 Fa SAL 40 BackspuMA %23 5S 13 T R Tab 10 Enter K D F S A S Caps Lock Shift Ctri Alt Alt Fr CtriIn order to determine if weather conditions play a significant role in how a disease effects wheat, fields of wheat are exposed to this disease over three consecutive summers, 2002-2004. The fields are later rated on a scale of 0.0 (resistant) to 10.0 (susceptible) based on how the disease has infected the field. The results are shown below along with the ANOVA table. At the 95% confidence level, compare the mean scores across the three years. 2002 2003 2004 7 7.3 5 4.7 8 3 8 5 2 3.3 3.3 7 6.3 4.7 7.3 7 3.7 8 7 4.3 6. 7 4.3 2 6.3 6.7 ANOVA Source of Variation df MS Treatment 20.97333 2 10.48667 4.127165 Error 76.22667 30 2.540889 Total 97.2 32
- A study of 420,039 cell phone users found that 131 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0443% for those not using cell phones. Complete parts (a) and (b). ..... a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. • D%A study of 420,097 cell phone users found that 137 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0311% for those not using cell phones. Complete parts (a) and (b). .... a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. %A researcher studying reaction time of drivers states that, "A 95% confidence interval for the mean time it takes for a driver to apply the brakes after seeing the brake lights on a vehicle in front of him is 1.2 to 1.8 seconds." What are the point estimate and margin of error for this interval? Point estimate = 1.5 seconds; margin of error = 0.95 seconds. Point estimate = 1.2 seconds; margin of error = 0.3 seconds. Point estimate = 1.5 seconds; margin of error = 0.6 seconds. Point estimate = 1.5 seconds; margin of error = 0.3 seconds. a O b O dRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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